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lys-0071 [83]
3 years ago
10

leon charged $75 at an interest rate of 12.5%. How much will leon have to pay after one month if he makes no payments?

Mathematics
2 answers:
Alexeev081 [22]3 years ago
3 0
I believe that the question is assuming this is taking place over one month here is what I think you would do.

1) 75/12.5 = 6
2) add that answer to 75, so 75+6, and you get 81
Tcecarenko [31]3 years ago
3 0

Answer:

<h2>$ 84.38</h2>

Step-by-step explanation:

Assuming the interest rate as monthly, he has to pay $ 84.38 after one month.

Because, if the interest rate is 12.5 %, that means $ 9.38 extra the initial $ 75.

Then, you need to add $ (75 + 9.38) = $ 84.38.

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What ia the common ratio of the sequence? -2 , 6, -18, 54,...
Jlenok [28]
Its a multiplication by -3 on each term, so I think you're gonna answer is by r=-3, maybe?
7 0
3 years ago
6x – 4y = -5<br>4x + 5y = -11​
kipiarov [429]

Answer:

x= -1.5, y= -1

Step-by-step explanation:

6x= -5+4y

x= (-5+4y) / 6

4((-5+4y) / 6) + 5y = -11

4(-5+4y) + 5*6y = -11*6

-20+16y+30y= -66

16y + 30y = -66+20 = -46

y(16 + 30) = -46

y= -46 / (16 + 30)

y= -46 / 46

y= -1

x= (-5+4(-1)) / 6

x= (-5-4) / 6

x= -9 /6

x= -1.5

3 0
3 years ago
Please answer this correctly without making mistakes
sveta [45]

Answer:

2282 tablespoons

and 1 teaspoon

Step-by-step explanation:

8 0
3 years ago
Kareem wrote the values shown below.
sweet [91]

Answer:  Option 'B' is correct.

Step-by-step explanation:

Since we have given that

[3.2] [2.7] [2.9] [4.8]

Since they are all of greatest integer functions i.e.

f(x) = [x]

It is known as greatest integer function whose value is always less than or equal to 'x'.

So, [3.2]=3

[2.7]=2

[2.9]=2

[4.8]=4

so, we can see that [2.7] and [2.9] is a equivalent pair.

Hence, Option 'B' is correct.

4 0
3 years ago
Read 2 more answers
Answer correctly please
Paul [167]

Answer:

\$272,49

Step-by-step explanation:

7. \displaystyle /text{The answer makes sense because since the depreciation rate is 15%, we know that we need to use the "exponential decay" formula.}

6. \displaystyle /text{After a depreciation rate of 15% for the past 8 years, the stock is now worth approximately $272,49.}

5. \displaystyle 1000[0,85]^8 = 272,490525 ≈ \$272,49

4. \displaystyle 1000 = a \\ -15\% + 100\% = 1 - r; 85\% = 1 - r \\ 8\:years = time\:[t]

3. \displaystyle /text{We need to use the "Exponential Decay" formula} - f(t) = a[1 - r]^t, where a > 0

2. \displaystyle /text{How much is the stock worth after a depreciation rate of 15% per year?}

1. \displaystyle /text{initial amount: $1000, a depreciation rate of 15%, and a time period of 8 years}

I am joyous to assist you anytime.

5 0
3 years ago
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