How many ways can a baseball manager arrange a batting order of 9 players?

Mathematics

1 answer:

agasfer [191]3 years ago

5 0

Answer:

A baseball team has 9 starting players. How many ways can the coach make out the batting order? 9! = 9 · 8 · 7 · 6 · 5 ·4 · 3 · 2 · 1 = 362,880 .

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4 years ago

sin theta = x , sec theta =y . find cot theta pls answer fast i need to verify my answer . you can directly write the answer no

Snowcat [4.5K]

Answer:

$\huge\boxed{\cot\theta=\dfrac{1}{xy}}$

Step-by-step explanation:

$\bold{METHOD\ 1}$

$\sin\theta=x\\\\\sec\theta=y\\\\\cot\theta=?\\\\\text{We know:}\\\\\sec x=\dfrac{1}{\cos x};\ \cot x=\dfrac{\cos x}{\sin x}\\\\\sec\theta=y\to\dfrac{1}{\cos \theta}=y\to\dfrac{\cos\theta}{1}=\dfrac{1}{y}\to\cos\theta=\dfrac{1}{y}\\\\\cot \theta=\dfrac{\frac{1}{y}}{x}=\dfrac{1}{xy}$

$\bold{METHOD\ 2}$

$\text{We know}\\\\\tan x=\dfrac{\sin x}{\cos x}\\\\\cot x=\dfrac{\cos x}{\sin x}=\dfrac{1}{\tan x}\\\\\sec x=\dfrac{1}{\cos x}\\\\\text{therefore}\\\\(sin x)(\sec x)=(\sin x)\left(\dfrac{1}{\cos x}\right)=\dfrac{\sin x}{\cos x}=\tan x\\\\\dfrac{1}{(\sin x)(\sec x)}=\dfrac{1}{\tan x}=\cot x$