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jok3333 [9.3K]
3 years ago
13

A glass is

Mathematics
2 answers:
serg [7]3 years ago
7 0

Answer:

Step-by-step explanation:

4/7 x + 70 cm^3 = 3/4 x          Subtract 4/7 x from both sides

3/4 x - 4/7 x = 70 cm^3          The lowest common denominator is 28

\frac{3*7*x}{4*7} - \frac{4*4x}{4*7} = 70 cc\\\frac{21*x}{28} - \frac{16*x}{28} = 70 cc\\\frac{5x}{28}= 70cc\\

5x = 70*28

5x = 1960                                Divide by 5

x = 1960/5

x = 392 cc

sergeinik [125]3 years ago
4 0

Answer:

  • 392 cm³

Step-by-step explanation:

<u>The difference of 3/4 and 4/7 of the volume is 70 cm:</u>

  • 3/4 - 4/7 = 7/7*3/4 - 4/4*4/7 = 21/28 - 16/28 = 5/28

5/28 of the volume is 70 cm³

<u>Divide both numbers by 5/28 to find the total volume of the glass:</u>

  • 70 : 5/28 = 70*28/5 = 392 cm³
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Answer:

Answer is 17

Step-by-step explanation:

-2 2/5 + 3 1/4

-12/5 +13/4

multiply both side with 20 we get

20* -12/5 +13/4 *20

-48 + 65

17

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an outfielder throws a ball to home plate. the balls path is modeled by the graph of y=x/5-x^2/1000 where x represents the horiz
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The coordinates of the vertex for the quadratic function are given as follows: (100,10).

<h3>What is the vertex of a quadratic equation?</h3>

A quadratic equation is modeled by:

y = ax^2 + bx + c

The vertex is given by:

(x_v, y_v)

In which:

  • x_v = -\frac{b}{2a}
  • y_v = -\frac{b^2 - 4ac}{4a}

In this problem, the function is given as follows:

y = -x²/1000 + x/5

y = -0.001x² + 0.2x.

Hence the coefficients are a = -0.001, b = 0.2, c = 0 and the coordinates of the vertex are given as follows:

  • x_v = -\frac{0.2}{2(-0.001)} = 100
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2 years ago
Assume that a randomly selected subject is given a bone density test. Those test scores are normally distributed with a mean of
jarptica [38.1K]

Answer:

The "probability that a given score is less than negative 0.84" is  \\ P(z.

Step-by-step explanation:

From the question, we have:

  • The random variable is <em>normally distributed</em> according to a <em>standard normal distribution</em>, that is, a normal distribution with \\ \mu = 0 and \\ \sigma = 1.
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Preliminaries

A z-score is a standardized value, i.e., one that we can obtain using the next formula:

\\ z = \frac{x - \mu}{\sigma} [1]

Where

  • <em>x</em> is the <em>raw value</em> coming from a normal distribution that we want to standardize.
  • And we already know that \\ \mu and \\ \sigma are the mean and the standard deviation, respectively, of the <em>normal distribution</em>.

A <em>z-score</em> represents the <em>distance</em> from \\ \mu in <em>standard deviations</em> units. When the value for z is <em>negative</em>, it "tells us" that the raw score is <em>below</em> \\ \mu. Conversely, when the z-score is <em>positive</em>, the standardized raw score, <em>x</em>, is <em>above</em> the mean, \\ \mu.

Solving the question

We already know that \\ z = -0.84 or that the standardized value for a raw score, <em>x</em>, is <em>below</em> \\ \mu in <em>0.84 standard deviations</em>.

The values for probabilities of the <em>standard normal distribution</em> are tabulated in the <em>standard normal table, </em>which is available in Statistics books or on the Internet and is generally in <em>cumulative probabilities</em> from <em>negative infinity</em>, - \\ \infty, to the z-score of interest.

Well, to solve the question, we need to consult the <em>standard normal table </em>for \\ z = -0.84. For this:

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  • Then, using the first row of the table, find -0.04 (which determines the second decimal place for the z-score.)
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Therefore, we obtain \\ P(z for this z-score, or a slightly more than 20% (20.045%) for the "probability that a given score is less than negative 0.84".

This represent the area under the <em>standard normal distribution</em>, \\ N(0,1), at the <em>left</em> of <em>z = -0.84</em>.

To "draw a sketch of the region", we need to draw a normal distribution <em>(symmetrical bell-shaped distribution)</em>, with mean that equals 0 at the middle of the distribution, \\ \mu = 0, and a standard deviation that equals 1, \\ \sigma = 1.

Then, divide the abscissas axis (horizontal axis) into <em>equal parts</em> of <em>one standard deviation</em> from the mean to the left (negative z-scores), and from the mean to the right (positive z-scores).  

Find the place where z = -0.84 (i.e, below the mean and near to negative one standard deviation, \\ -\sigma, from it). All the area to the left of this value must be shaded because it represents \\ P(z and that is it.

The below graph shows the shaded area (in blue) for \\ P(z for \\ N(0,1).

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Answer:

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sooo

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Step-by-step explanation:

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