Let us say that:
a = ones
b = fives
c = twenties
So that the total money is:
1 * a + 5 * b + 20 * c = 229
=> a + 5b + 20c = 229 -->
eqtn 1
We are also given that:
c = a – 5 -->
eqtn 2
a + b + c = 30 -->
eqtn 3
Rewriting eqtn 3 in terms of b:
b = 30 – a – c
Plugging in eqtn 2 into this:
b = 30 – a – (a – 5)
b = 35 – 2a -->
eqtn 4
Plugging in eqtn 2 and 4 into eqtn 1:
a + 5(35 – 2a) + 20(a – 5) = 229
a + 175 – 10a + 20a – 100 = 229
11a = 154
a = 14
So,
b = 35 – 2a = 7
c = a – 5 = 9
Therefore there are 14 ones, 7 fives, and 9 twenties.
i really cant see what it says sorry
Answer:
Step-by-step explanation:
A. Directrix: y = 4-6 = -2
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B. Axis of symmetry: x = 6
Axis of symmetry intersects directrix at (6,-2)
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C . Vertex is halfway between focus and directrix, at (6,1)
:::::
D. The focus lies above the directrix, so the parabola opens upwards.
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E. Focal length p = 1/(4×0.5)
:::::
F. p = 0.5
::::
G. y = 0.5(x-6)² + 1
Answer: 300 m
<u>Step-by-step explanation:</u>
= 150 + 150
= 300
Answer:
4(2x - 5)
Step-by-step explanation:
Rewrite "20" as 4 * 5
Rewrite "8" as 4 * 2
=4 * 2x - 4 * 5
Factor out common term "4"
=4(2x - 5) <------ Your answer.
