Answer:
The equation written in the standard form is written as
ax^4 + bx+c
where a and b are the coefficients of the second-order and first-order term, while c is the constant term.
The equation we have in this problem is
By comparing (1) with (2), we immediately see that
A = -3x^4
B = 7x
C = 2
Step-by-step explanation:
Hope this helps :)
Answer:
h = 61.25 m
Step-by-step explanation:
It is given that,
The initial velocity of the ball, v = 60 m/s
It is thrown from a height of 5 feet, 
We need to find the maximum height it reaches. The height reached by the projectile as a function of time t is given by :
Putting all the values,
.....(1)
For maximum height, put
Put t = 1.875 in equation (1)
So, the maximum height reached by the ball is 61.25 m.
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Answer:
2 touchdowns, 3 field goals
Step-by-step explanation:
The number of touchdowns cannot be more than 3, so it is relatively easy to find the solution by trial and error.
23 is not divisible by 3, so 0 touchdowns is not a solution
23 -7 = 16 is not divisible by 3, so 1 touchdown is not a solution
23 -14 = 9 is divisible by 3, so 2 touchdowns and 3 field goals is a solution
21 -21 = 2 is not divisible by 3, so there is only one solution.
Answer: 48 sold-out performances must be played in order for you to break even.
Step-by-step explanation:
Let x represent the number of sold-out performances must be played in order for you to break even.
You invest in a new play. The cost includes an overhead of $30,000, plus production costs of $2500 per performance. This means that the total cost of x sold out performances would be
2500x + 30000
A sold-out performance brings you $3125. This means that he total revenue from x sold out performances would be
3125x
To break even, cost = revenue
Therefore,
2500x + 30000 = 3125x
3125x - 2500x = 30000
625x = 30000
x = 30000/625
x = 48
