Answer:
x=-22/4
y=-3
Step-by-step explanation:
3x-2y=-5
4x+2y=-16
we <u>add</u> the equation
7y=-21
y=-3
then we find the x by taking a random equation
I take 4x+2y=-16
4x+2(-3)=-16
4x-6=-16
4x=-22
x=-22/4
Answer:
∠A=65º
Step-by-step explanation:
- A angle of a line is 180º, so we can say that angle ABC=(180-6x)º
- The interior angkes of a triangle is 180º, so (x+40)º+(3x+10)º+(180-6x)º=180º
- Remove parenthesis, x+40+3x+10+180-6x=180
- Combine like terms, -2x+230=180
- Subtract 180, -2x=-50
- Divide by -2, so x=25
Now:
- ∠CAB=(25+40)º=65º
- ∠ABC=[180-6(25)]º=30º
- ∠BCA=[3(25)+10]=85º
Answer:
The second number after the decimal point- the 6
To find the X intercept make y =0. Then factor out a negative on the side with the equation for each of the terms, so it becomes
0=-(x^2+x+3)
0=(x^2+X+3)
0-3=(x^2+X)
-3=x(X+1)
-3=X, X intercept -3,0
-3=(X+1)
-4=X, X intercept -4,0.
These are possible X intercepts you can check by using quadratic formula as well.
The ball will be at height 19 feet first at 0.7 sec and then at 1.42 sec.
<u>Explanation:</u>
We need to find the time at which the ball will be at height 19 feet.
Equation:
h = 3 + 34t - 16t²
19 = 3 + 34t - 16t²
16 = -16t² + 34t
-16t² + 34t - 16 = 0
On solving the equation, we get
t1 = 0.7 s and t2 = 1.42s
Therefore, the ball will be at height 19 feet first at 0.7 sec and then at 1.42 sec.
