16/21 is your answer
You can take a 2 out of both numbers to get your answer
I hope this helped! :)
she used GF=2BG,but the statement is correct BG=2GF
Given:
The expression is:
![25-10\div 2+3](https://tex.z-dn.net/?f=25-10%5Cdiv%202%2B3)
To find:
Part A: The expression using parentheses so that the expression equals 23.
Part B: The expression using parentheses so that the expression equals 3.
Solution:
Part A:
In option A,
![(25-10)\div 2+3=15\div 2+3](https://tex.z-dn.net/?f=%2825-10%29%5Cdiv%202%2B3%3D15%5Cdiv%202%2B3)
[Using BODMAS]
![(25-10)\div 2+3=10.5](https://tex.z-dn.net/?f=%2825-10%29%5Cdiv%202%2B3%3D10.5)
In option B,
![25-10\div (2+3)=25-10\div 5](https://tex.z-dn.net/?f=25-10%5Cdiv%20%282%2B3%29%3D25-10%5Cdiv%205)
[Using BODMAS]
![25-10\div (2+3)=23](https://tex.z-dn.net/?f=25-10%5Cdiv%20%282%2B3%29%3D23)
In option C,
![(25-10)\div (2+3)=15\div 5](https://tex.z-dn.net/?f=%2825-10%29%5Cdiv%20%282%2B3%29%3D15%5Cdiv%205)
![(25-10)\div (2+3)=3](https://tex.z-dn.net/?f=%2825-10%29%5Cdiv%20%282%2B3%29%3D3)
In option D,
![25-(10\div 2)+3=25-5+3](https://tex.z-dn.net/?f=25-%2810%5Cdiv%202%29%2B3%3D25-5%2B3)
[Using BODMAS]
![25-(10\div 2)+3=23](https://tex.z-dn.net/?f=25-%2810%5Cdiv%202%29%2B3%3D23)
After the calculation, we have
and
.
Therefore, the correct options are B and D.
Part B: From part A, it is clear that
![(25-10)\div (2+3)=3](https://tex.z-dn.net/?f=%2825-10%29%5Cdiv%20%282%2B3%29%3D3)
Therefore, the correct option is C.
Answer:
a+51=90
a+51+90=180
39
Step-by-step explanation:
hope this helped :)