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2 years ago

Divide: 6 ÷ 1/2=12

Mathematics

2 answers:

Debora [2.8K]2 years ago

8 0

Answer:

1=6

2=2

3=12

edge 2021 the 1st girl was right for the 2nd one but the rest was wrong..

Step-by-step explanation:

schepotkina [342]2 years ago

6 0

I believe the answers are:
1. Twelve circles
2. Two equal parts
3. 6 parts would be shaded

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Naeem weighs different salad takeout containers. The containers respectively weigh 4.5 ounces, 5.01 ounces, 5.3 ounces, 4.75 oun

shusha [124]

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3 years ago

Simplify the expression.

user100 [1]

Ur answer is. 5 y^2+4y+14 because I went through it in class

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3 years ago

What is 14 10/8 simplified?

mina [271]

14 10/8 is equal to 15 2/8 which cnman simplify down to 15 1/4. So, the simplest you can get is 15 1/4. I hope this helps!

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3 years ago

1. (a). A police car, approaching right-angled intersection from the north, is chasing a speedmg

tamaranim1 [39]

Answer:

<em>The SUV is running at 70 km/h</em>

Step-by-step explanation:

<u>Speed As Rate Of Change </u>

The speed can be understood as the rate of change of the distance in time. When the distance increases with time, the speed is positive and vice-versa. The instantaneous rate of change of the distance allows us to find the speed as a function of time.

This is the situation. A police car is 0.6 Km above the intersection and is approaching it at 60 km/h. Since the distance is decreasing, this speed is negative. On the other side, the SUV is 0.8 km east of intersection running from the police. The distance is increasing, so the speed should be positive. The distance traveled by the police car (y) and the distance traveled by the SUV (x) form a right triangle whose hypotenuse is the distance between them (d). We have:

$d=\sqrt{x^2+y^2}$

To find the instant speeds, we need to compute the derivative of d respect to the time (t). Since d,x, and y depend on time, we apply the chain rule as follows:

$\displaystyle d\ '=\frac{x.x'+y.y'}{\sqrt{x^2+y^2}}$

Where x' is the speed of the SUV and y' is the speed of the police car (y'=-60 km/h)

We'll compute :

$d=\sqrt{(0.8)^2+(0.6)^2}=\sqrt{0.64+0.36}$

$d=1\ km$

We know d'=20 km/h, so we can solve for x' and find the speed of the SUV

$\displaystyle \frac{x.x'+y.y'}{\sqrt{x^2+y^2}}=20$

Thus we have

$x.x'+y.y'=20$

Solving for x'

$\displaystyle x'=\frac{20-y.y'}{x}$

Since y'=-60

$\displaystyle x'=\frac{20+0.6(60)}{0.8}$

$x'=70\ km/h$

The SUV is running at 70 km/h

7 0

3 years ago

write an equation of a line that passed through the point (2,0) and is a perpendicular to the line y=-1.5+3

kotegsom [21]

You will be using the equation y = mx + b

The only variables you need to find are "m" and "b"

For the equation of a line to be perpendicular to the given line, the slope will have to be the opposite of the given slope. Or you have to flip the sign and the number of the given slope to get your new slope.

For example:

m = -2

perpendicular slope = 1/2(positive)

m = 3/4

perpendicular slope = -4/3(negative)

The slope of the line is -1.5 or -3/2

Your new slope is 2/3

y = 2/3x + b

To find "b", you plug in the point (2,0) into the equation.

0 = 2/3(2) + b

0 = 4/3 + b

-4/3 = b

Your new equation is y = 2/3x - 4/3

7 0

3 years ago