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Varvara68 [4.7K]
3 years ago
7

If m_PQT=(3x+47) and m_SQR=(6x+25), find m_SQR

Mathematics
1 answer:
marishachu [46]3 years ago
7 0

Answer:

6x+25

Step-by-step explanation:

here is given that

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HELP what is 3( 2+5) - 5 (3) + 8
neonofarm [45]

Answer:

14

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
I got 3 angles and they make 180° one of them is 6x - 10°. Another one is 4x + 6°. And the last one is 7x + 14°.
fiasKO [112]

Answer:

angle a=50      angle b= 46      angle c= 84

Step-by-step explanation:

6x-10+4x+6+7x+14=180

17x +10=180

-10                      -10

17x=170

/10     /10

x=10

6x-10  

(6 x 10) -10= 50

4x+6

(4 x 10) +6= 46

7x+14

(7 x 10) +14= 84

50+46+84=180

3 0
3 years ago
Andrew is looking into prices for cable for his new home. He received the following breakdown for monthly prices.
GuDViN [60]
Given:

551.88 + 341.64b

The coefficient of "B" is 341.64, the best statement that applies to it is:

<span>D. It is the cost for one cable box with DVR and HD service for one year.

</span>Cable boxes: $ 3.49 per cable box
HD Service:   $ 9.99 per cable box
<span>DVR:          <u>   $ 14.99 per cable box</u>
</span>Total :            $ 28.47
multiply        <u>     12 months</u>
Annual cost  $341.64
8 0
3 years ago
The polynomial equation x^4 + x^3 + x^2 + x + 1 = 0 has zero positive real roots. Please select the best answer from the choices
const2013 [10]

There are zero positive real roots for the given polynomial equation x^4 + x^3 + x^2 + x + 1 = 0. This is explained by Descarte's rule of signs. So, the best choice is T (true).

<h3>What is Descarte's rule of signs?</h3>
  • Descarte's rule of signs tells about the number of positive real roots and negative real roots.
  • The number of changes in signs of the coefficients of the terms of the given polynomial f(x) gives the positive real zeros of the polynomial.
  • The number of changes in signs of the coefficients of the terms of the given polynomial when f(-x) gives the negative real zeros of the polynomial.

<h3>Calculation:</h3>

The given polynomial equation is x^4 + x^3 + x^2 + x + 1 = 0

On applying Descarte's rule of signs,

f(x)=x^4 + x^3 + x^2 + x + 1

Since there are no changes in the signs of the coefficients of any of the terms in the above polynomial, the polynomial has no positive real roots.

f(-x)=(-x)^4+(-x)^3+(-x)^2+(-x)+1\\      = x^4-x^3+x^2-x+1

Since there are four changes in the signs of the coefficients of the terms of the given polynomial when f(-x), the polynomial has 4 negative real roots.

Therefore, the given polynomial equation has zero positive real roots. So, the correct choice is T(true).

Learn more about Descarte's rule of signs here:

brainly.com/question/11590228

#SPJ1

5 0
2 years ago
Find the perimeter of the right triangle. If necessary, round to the nearest tenth.
puteri [66]

Answer:

a. 12 yd

Step-by-step explanation:

\sqrt{ {15}^{2} -  {9}^{2}  }  = 12

7 0
3 years ago
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