Given:
The point 
divides the line segment joining points 
and 
.
To find:
The ratio in which he point P divides the segment AB.
Solution:
Section formula: If a point divides a segment in m:n, then the coordinates of that point are,
Let point P divides the segment AB in m:n. Then by using the section formula, we get
On comparing both sides, we get
Multiply both sides by 4.
It can be written as
Therefore, the point P divides the line segment AB in 1:5.
Answer:
x = 6
Step-by-step explanation:
3x + 4 = 5x - 8
==> add 8 to both sides
in doing so we get 3x + 4 + 8 = 5x - 8 + 8
the -8 and the +8 cancels out and 4 + 8 = 12
we are left with 3x + 12 = 5x
==> subtract 3x from both sides
in doing so we get 3x - 3x + 12 = 5x - 3x
the 3x and -3x cancel out and 5x - 3x = 2x
we are left with 12 = 2x
==> divide both sides by 2
in doing so we get 12/2 which equals 6 and 2x/2x which leaves us with
6 = x
Easy, so absolute value makes anything inside into positive
|x|=2
therefor x=-2 or x=2 since it would be made posotive
answer is -2 and 2
8(4a+2b)
The equivalent is 32a+16b (B)
X is 19
Explanation: because the opposite side of the angle is 134 degrees the other side also has to be 134 degrees. So we do 134-20 which is 114 and then 114 divided by 6 because the number next to x is 6 and the number that is x has to be 19 as 19x6 is 114.
I think this is the right answer and I hope it helps :)
