To solve this, let us first imagine a smaller triangle
created by the head of Jim (A), the top of the lamp post (B), and somewhere on
the body of the lamp post which is directly perpendicular to the head of Jim
(C).
CB = 16 – 6 = 10 ft
AC = 4 ft
Calculate for angle B using tan function:
tan B = AC / CB
B = tan^-1 (4 / 10)
B = 21.8°
Now imagine a bigger triangle created by the tip of
shadow (D), the top of the lamp post (B), and the base of the lamp post (E).
BE = 16 ft
B = 21.8°
We can calculate for DE using tan function:
tan B = DE / BE
(16 ft) tan 21.8 = DE
DE = 6.4 ft
Since Jim is 4ft away from the base of the lamp post,
therefore the length of the shadow is:
6.4 ft – 4 ft
= 2.4 ft
Therefore the length of Jim’s shadow is 2.4 ft long
Answer:
-4w + 32
Step-by-step explanation:
4 (-w + 8)
= (-4 × w) + (4 × 8)
= -4w + 32
Hope it helps :)
Please mark my answer as the brainliest
Answer:
3x⁵+8x³+5x²-2x+3
Step-by-step explanation:
3x⁵+8x³+5x²-2x+3
I saw someone else with this exact question...
Question 4:
SQUARE BASE pyramid has obviously a square base and if it’s a pyramid it has triangular sides. Also the base has 4 vertices and then the one on top equals 5 vertices. Finally it has 8 edges.
Question 5:
Circle
Comment on this answer if you need further explanations!!!