Which expression could not be used to evaluate 25

Jackson bought 555 ounces of raisins for \$4$4dollar sign, 4.

Fynjy0 [20]

Answer:

Part a) The raisins cost $0.8 per ounce

Part b) 1.25 ounces

Step-by-step explanation:

<u><em>The correct question is</em></u>

Jackson bought 5 ounces of raisins for $4 dollars.

a) How much do raisins cost per ounce?

b) How many ounces of raisins can be bought for $1?

Part a) How much do raisins cost per ounce?

we know that

To find out the unit rate divide the total cost by the total weight

so

$\frac{4}{5} =\$0.8\ per\ ounce$

therefore

The raisins cost $0.8 per ounce

Part b) How many ounces of raisins can be bought for $1?

we know that

The raisins cost $0.8 per ounce

using proportion

Find out how many ounces of raisins can be bought for $1

Let

x -----> the ounces of raisins

$\frac{1}{0.8}=\frac{x}{1}\\\\x= 1.25\ ounces$

8 0

2 years ago

Read 2 more answers

At the start of the year, 15 chameleons were introduced into a zoo. The population of chameleons is expected to grow at a rate o

bearhunter [10]

Answer:

option-B

Step-by-step explanation:

We are given

At the start of the year, 15 chameleons were introduced into a zoo

so, $P_0=15$

The population of chameleons is expected to grow at a rate of 41.42% every year

so, r=0.4142

and x represents the number of years since the chameleons were introduced into the zoo

now, we can set equation to find total population

and we get

$P(x)=P_0(1+r)^x$

now, we can plug values

$P(x)=15(1+0.4142)^x$

$P(x)=15(1.4142)^x$

Average rate of change between 2 years and 4 years:

we can use formula

$A_1=\frac{P(4)-P(2)}{4-2}$

now, we can plug values

$A_1=\frac{15(1.4142)^{4}-15(1.4142)^{2}}{4-2}$

$A_1=14.99914$

Average rate of change between 4 years and 6 years:

we can use formula

$A_2=\frac{P(6)-P(4)}{6-4}$

now, we can plug values

$A_2=\frac{15(1.4142)^{6}-15(1.4142)^{4}}{6-4}$

$A_2=29.99770$

Average rate of change between 6 years and 8 years:

we can use formula

$A_3=\frac{P(8)-P(6)}{8-6}$

now, we can plug values

$A_3=\frac{15(1.4142)^{8}-15(1.4142)^{6}}{8-6}$

$A_3=59.99425$

now, we will check each options

option-A:

we can see that

$A_3-A_2=30$

So, this is FALSE

option-B:

$A_1=\frac{1}{2}A_2$

So, this is TRUE

option-C:

This is FALSE

option-D:

we got

$A_1=\frac{1}{2}A_2$

so, this is FALSE

5 0

3 years ago

Given BD= 24 and PC= 13, find PB

ipn [44]

PB = 12 (P=1, B=2) Numerical values are assigned to each letter and each letter takes on a single number.

8 0

3 years ago

A town has a population of 1000 people at time t equals 0.The population increases by 30 people a year. Write a formula for the

anygoal [31]

The given point (t, P) is (0, 1000), and the slope is given as ∆P/∆t = 30. Using the point-slope form of the equation for a line, the equation can be written as

... P = 30t + 1000

5 0

3 years ago

Please help I think these are the right answers!!!

Papessa [141]

We performed the following operations:

$f(x)=\sqrt[3]{x}\mapsto g(x)=2\sqrt[3]{x}=2f(x)$

If you multiply the parent function by a constant, you get a vertical stretch if the constant is greater than 1, a vertical compression if the constant is between 0 and 1. In this case the constant is 2, so we have a vertical stretch.

$g(x)=2\sqrt[3]{x}\mapsto h(x)=-2\sqrt[3]{x}=-g(x)$

If you change the sign of a function, you reflect its graph across the x axis.

$h(x)=-2\sqrt[3]{x}\mapsto m(x)=-2\sqrt[3]{x}-1=h(x)-1$

If you add a constant to a function, you translate its graph vertically. If the constant is positive, you translate upwards, otherwise you translate downwards. In this case, the constant is -1, so you translate 1 unit down.

5 0

2 years ago

Which expression could not be used to evaluate 25 · 18