Answer:
a) h(t) = -16t² + 56t; b) the graph is attached; c) maximum height is 49 feet, it takes 1.75 seconds to reach the maximum, and it is in the air for 3.5 seconds.
Step-by-step explanation:
Equations for these situations are in the form
h(t) = -16t² + v₀t + h₀, where t is the tie in seconds, v₀ is the initial velocity and h₀ is the initial height. The initial height in this case is 0, since it is launched from the ground; and the initial velocity is 56. This gives us the function
h(t) = -16t² + 56t
The graph is attached.
Using the graph, we can trace the function to the maximum. The y-value of the maximum, or the maximum height, is 49 feet. The x-value of the maximum, the time it takes, is 1.75 seconds.
The roots of this equation are at x = 0 and x = 3.5. This means the rocket is in the air for 3.5-0 = 3.5 seconds.
Answer:
Identity Property
Step-by-step explanation:
Answer:
Step-by-step explanation:
x is 1,2,3,4,5
y is 14,13,12,11,10
Answer:
hey theres no pic
Step-by-step explanation:
Answer:
KJ and JH
Step-by-step explanation:
because all of the rest are congruent except KJ and JH
