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iragen [17]
2 years ago
11

Which division problem does the number line below best illustrate?

Mathematics
1 answer:
DaniilM [7]2 years ago
8 0

Answer:

A. 10 divided by 2=5 i think

Step-by-step explanation:

it look like it is

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A gym charges a $49.95 activation fee and $17.50 per month for a membership. If you spend $364.95 for how many months do you hav
olga nikolaevna [1]
18 months.

$364.95 - $49.95 = $315

$315 / $17.50 = 18
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3 years ago
Help please and sorry it’s not clear
aliina [53]

Answer:

C

Step-by-step explanation:

8 0
2 years ago
The sum of a positive integer and a negative integer is...
murzikaleks [220]
Depends is the positive integer is larger than the negative interger for example -10+5=-5.
10+-4=6
8 0
3 years ago
Mr. See weights his grades. Tests are worth 60%, quizzes are worth 25% and homework is 15%. Joey's test average is an 82, his qu
goldenfox [79]

Answer:

83.15

Step-by-step explanation:

Joey's current grade can be determined by weighting his scores with the weights given and adding the results

Tests = 0.6 x 82 = 49.2

Quizzes = 0.25 x 77 = 19.25

homework = 0.15 x 98 = 14.7

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4 0
3 years ago
The height H of an ball that is thrown straight upward from an initial position 3 feet off the ground with initial velocity of 9
mariarad [96]

Answer:

The ball will be 84 feet above the ground 1.125 seconds and 4.5 seconds after launch.

Step-by-step explanation:

Statement is incorrect. Correct form is presented below:

<em>The height </em>h(t)<em> of an ball that is thrown straight upward from an initial position 3 feet off the ground with initial velocity of 90 feet per second is given by equation </em>h(t) = 3 +90\cdot t -16\cdot t^{2}<em>, where </em>t<em> is time in seconds. After how many seconds will the ball be 84 feet above the ground. </em>

We equalize the kinematic formula to 84 feet and solve the resulting second-order polynomial by Quadratic Formula to determine the instants associated with such height:

3+90\cdot t -16\cdot t^{2} = 84

16\cdot t^{2}-90\cdot t +81 = 0 (1)

By Quadratic Formula:

t_{1,2} = \frac{90\pm \sqrt{(-90)^{2}-4\cdot (16)\cdot (81)}}{2\cdot (16)}

t_{1} = 4.5\,s, t_{2} = 1.125\,s

The ball will be 84 feet above the ground 1.125 seconds and 4.5 seconds after launch.

3 0
3 years ago
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