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const2013 [10]
3 years ago
11

jada has some money she sells 1 balloon for 5cent. Now she has 13cent. How much money did jada have before selling the balloon?​

Mathematics
1 answer:
seraphim [82]3 years ago
3 0

Answer:

8 cents

Step-by-step explanation:

To find out how much money Jada had before seling the balloon, we can subtract 5 from 13.

13 - 5 = 8

So, Jada had 8 cents before selling the balloon.

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Factor out the coefficient of the variable 1/2q plus 5/2
Iteru [2.4K]
I believe you do it like this:
1/2 Q+5/2
divide 1/2 into each term
to divide multiply by the reciprocal
1/2 x2/1= 1
5/2 x 2/1=5

1/2(Q+5) 
8 0
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iren [92.7K]

Answer: -6r + 6

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4 0
3 years ago
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Evaluate using <br> Definite integrals
swat32

Since [0,4]=[0,1]\cup(1,4], we can rewrite the integral as

\displaystyle \int_0^1f(t)\;dt + \int_1^4 f(t)\; dt

Now there is no ambiguity about the definition of f(t), because in each integral we are integrating a single part of its piecewise definition:

\displaystyle \int_0^1f(t)\;dt = \int_0^11-3t^2\;dt,\quad \int_1^4 f(t)\; dt = \int_1^4 2t\; dt

Both integrals are quite immediate: you only need to use the power rule

\displaystyle \int x^n\;dx=\dfrac{x^{n+1}}{n+1}

to get

\displaystyle \int_0^11-3t^2\;dt = \left[t-t^3\right]_0^1,\quad \int_1^4 2t\; dt = \left[t^2\right]_1^4

Now we only need to evaluate the antiderivatives:

\left[t-t^3\right]_0^1 = 1-1^3=0,\quad \left[t^2\right]_1^4 = 4^2-1^2=15

So, the final answer is 15.

4 0
3 years ago
What is the value of 4/7 x 0.3 ÷ 1/6
Alik [6]
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5 0
3 years ago
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I need help with this ASAP and can you explain so i can understand?!
Elanso [62]

Answer:

Adult tickets sold =  225

Student Tickets sold =  375

Step-by-step explanation:

Let:

Adult tickets sold = x

Student Tickets sold = y

Total tickets sold = 600

So, we can write: x+y = 600

Total money collected = 3037.50

Cost of 1 Adult ticket = $6.00

Cost of one Student ticket = $4.50

So, we can write: 6x+4.5y=3037.50

Now, we get a system of equations, that if solved we can find values of x and y

Let:

x+y = 600--eq(1)\\6x+4.5y=3037.50--eq(2)

We can solve using substitution method.

Finding value of x from eq(1) and putting it in eq(2)

We\:have\\x+y=600\\x=600-y

Put in eq(2)

6x+4.5y=3037.50\\6(600-y)+4.5y=3037.50\\3600-6y+4.5y=3037.50\\-1.5y=3037.50-3600\\-1.5y=-562.5\\y=\frac{-562.5}{-1.5}\\y=375

So, we get value of y = 375

Now put value of y in eq(1) to find value of x

x+y=600\\Put\:y=375\\x+375=600\\x=600-375\\x=225

So, we get value of x = 225

The Tickets sold will be:

Adult tickets sold = x = 225

Student Tickets sold = y = 375

3 0
2 years ago
Read 2 more answers
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