(p³)(2p² - 4p)(3p² - 1) = (p³)(2p²*3p² - 4p*3p² - 1*2p² - 4p*(-1)) =
= (p³)(6p⁴ - 12p³ - 2p² + 4p)
Answer: A)
Answer:
Jay started with $148.5 and Kay with $24.75.
Step-by-step explanation:
With the information provided you know that Jay had 6 times as much money as Kay wich can be expressed as:
J=6K, where
J is the money Jay had
K is the money Kay had
Also, you know that Jay gave Kay $33 and Jay now has twice as much money as Kay, which would be:
J-33=2(K+33)
Now, you can replace J=6K in this equation and solve for K:
6K-33=2K+66
6K-2K=66+33
4K=66
K=24.75
Then, you can replace the value of K in J=6K:
J=6*24.75
J=148.5
According to this, the answer is that Jay started with $148.5 and Kay with $24.75.
If angle AEC is 90° and angle AEB bisects it and is 45° that right there proves that angle AEB bisects angle AEC
Answer:
The answer is 96 yd 2
Step-by-step explanation:
5x7=35
4x7=28
3x7=21
then you add all of the total values together:
35+28+21+12=96
