The slope of the line which passes through (19,-16) and (-7,-15) is -1/26.
Given that the points through which the line passes is (19,-16) and (-7,-15).
We are required to find the slope of the line which passes through (19,-16) and (-7,-15).
The slope of a line is basically a measure of its steepness.It is basically the difference between y coordinate divided by the difference between x coordinate. We can form an equation with the help of the slope.
Points=(19,-16) and (-7,-15)
Slope=(-15+16)/(-7-19)
=1/-26
=-1/26
Hence the slope of the line which passes through (19,-16) and (-7,-15) is -1/26.
Learn more about slope at brainly.com/question/3493733
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Answer:
The value of x for equation is 3.4
The value of y for equation is 5.2
Step-by-step explanation:
Given as :
The two linear equation are
2 x + y = 12 ........A
4 x - 3 y = 2 .........B
Now, Solving both equations , we get
3 × ( 2 x + y ) + (4 x - 3 y) = 3 × 12 - 2
Or, 6 x + 3 y + 4 x - 3 y = 36 - 2
Or, (6 x + 4 x) + (3 y - 3 y) = 34
Or, 10 x + 0 = 34
∴ x = 
i.e x = 3.4
So, The value of x for equation , x = 3.4
Put the value of x into eq A
∵ 2 x + y = 12
Or, y = 12 - 2 x
Or, y = 12 - 2 × 3.4
Or, y = 12 - 6.8
∴ y = 5.2
So, The value of y for equation , y = 5.2
Hence, The value of x for equation is 3.4 and The value of y for equation is 5.2 Answer
The answer is D :) II hope that this helps and if you need a bigger description I can help
Step 1
Find the area of one equilateral triangle
Applying the law of sines

in this problem
a=b=7 cm
C=60 degrees
so

cm²
Step 2
To calculate the area of the hexagon multiply the area of one equilateral triangle by 
cm²
therefore
the answer is the option
73.5 sqrt 3cm²