Answer:
C.Fewer differences in the amino acid sequencing of a protein show a greater evolutionary relatedness.
Explanation:
Since there are less differences it indicates that they are more related.
Gel electrophoresis is a method used for the separation of DNA fragments based on their sizes. We have labelled the steps and you can know the sequence of the steps by going through attached image.
The technique is very important for the molecular analysis and identification of new genes. It is also useful in identification of genetic sequence of a particular gene.
Hope it helps!
Answer:
H>D>G>J>A>E>I>B>F>C
H: DIAMOND
D: CORUNDUM
G: TOPAZ
J: QUARTZ
A: FELDSQUAR
E: APATITE
I: FLOURITE
B: CALCITE
F: GYPSUM
C: TALC
Explanation:
I found the full question on the test . Following is the complete answer
1. J>A>E and J>A>I
2. C is the softest. C is Talc
3. E>I ⇔ J>A>E>I
4. F>C
5. On the full question, B can scratch mineral F but it can be scratched by all the other minerals except C. B>F>C
6. H is the hardest. H is Diamond
7. D is Corundum
8. H>D>G>J
Combine all the information, we have the following:
H>D>G>J>A>E>I>B>F>C
Answer:
c. is inactivated by binding lactose
Explanation:
Lactose is a sugar mostly present in milk or dairy products. It is degraded in the body by an enzyme called LACTASE. Since lactase is an enzyme (protein), it must be encoded by a structural gene (Lac gene). However, the expression of this structural gene can be inhibited by the absence of lactose.
Ideally, when lactose is present, it binds to a DNA binding protein called Lac repressor protein (inhibitor) causing the inhibitor protein to lose its shape and fall off, allowing transcription of the lac gene to occur. In other words, the presence of lactose deactivates the inhibitory function of lactose repressor protein.
25...50.
Let’s assign the dominant allele letter T and the recessive allele letter t. Next step we draw the punnet square below and determine the possible genotype of the offsprings with regards to this trait. It is therefore evident that the probability that the offspring will have the illness (genotype tt) is 25%
50% will be carriers (genotype Tt) like their parents