The number of solutions of a quadratic equation
ax^2+bx+c=0
Depends on its discriminant
/Delta=b^2-4ac
If /Delta>0 there are two distinct solutions
If /Delta=0 there are two coincident solutions
If /Delta<0 there are no solutions.
We know that there are two real solutions (I assume you mean distinct solutions), so we know that the discriminant is positive:
The number of solutions of a quadratic equation
Depends on its discriminant
If there are two distinct solutions
If there are two coincident solutions
If there are no solutions.
We know that there are two real solutions (I assume you mean distinct solutions), so we know that the discriminant is positive:
b^2-4ac=9+28t>0\iff t>-\dfrac[9][28]
Step-by-step explanation:
So for this question just substitute the value and work out. I thought it it to the power of 2 as I can't tell from the question.
After two years with the interest compounded annually the amount would be $1,060.90.
After two years with the interest compounded monthly the amount would be $1,061.76.
After two years with the interest compounded quarterly the amount would be $1,061.60.
After two years with the interest compounded semiannually the amount would be $1,061.36.
x=ferns ; y=ivy
12x+8y=260
6x+15y=240
x=60 -(15/6)y
12(60+ (15/6)y + 8y = 260
x=60 -(15/6)y
720 - 30y + 8y = 260
x=60- (15/6)y
-30y +8y= 260-720 ==> -22y= -460
x=60 -(15/6)y
y= (-460)/(-22)= 20.9090909091
y=20.90
x=60 -(15/6)×20.90= 7.75
×(ferns)=7.75$
y(ivy)=20.90$
