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Artist 52 [7]
3 years ago
5

Gary attended a Saints game last night. The ticket to get into the game was $39.00 and hot dogs cost $5.50 each.

Mathematics
2 answers:
stealth61 [152]3 years ago
8 0

Answer:

3 hot dogs

Step-by-step explanation:

gtnhenbr [62]3 years ago
4 0

Answer:

He could get 3 hotdogs

Step-by-step explanation:

60-39 is 21

21 divided by 5.50(cost of hotdogs) is 3.81(repeating)

so he could buy 3 whole hotdogs

hope this helps

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guapka [62]

Find the vertex: -4x^2 + 16x - 7​

Vertex = ( x, f(x)).

x = -b/2a

x = -16/2(-4)

x = -16/-8

x = 2

f(x) = -4x^2 + 16x - 7

Let x = 2

f(2) = -4(2)^2 + 16(2) - 7

f(2) = -4(4) + 32 - 7

f(2) = -16 + 32 - 7

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3 years ago
Two different cars each depreciate to 60% of their respective original values. The first car depreciates at an annual rate of 10
zvonat [6]

The approximate difference in the ages of the two cars, which  depreciate to 60% of their respective original values, is 1.7 years.

<h3>What is depreciation?</h3>

Depreciation is to decrease in the value of a product in a period of time. This can be given as,

FV=P\left(1-\dfrac{r}{100}\right)^n

Here, (<em>P</em>) is the price of the product, (<em>r</em>) is the rate of annual depreciation and (<em>n</em>) is the number of years.

Two different cars each depreciate to 60% of their respective original values. The first car depreciates at an annual rate of 10%.

Suppose the original price of the first car is x dollars. Thus, the depreciation price of the car is 0.6x. Let the number of year is n_1. Thus, by the above formula for the first car,

0.6x=x\left(1-\dfrac{10}{100}\right)^{n_1}\\0.6=(1-0.1)^{n_1}\\0.6=(0.9)^{n_1}

Take log both the sides as,

\log 0.6=\log (0.9)^{n_1}\\\log 0.6={n_1}\log (0.9)\\n_1=\dfrac{\log 0.6}{\log 0.9}\\n_1\approx4.85

Now, the second car depreciates at an annual rate of 15%. Suppose the original price of the second car is y dollars.

Thus, the depreciation price of the car is 0.6y. Let the number of year is n_2. Thus, by the above formula for the second car,

0.6y=y\left(1-\dfrac{15}{100}\right)^{n_2}\\0.6=(1-0.15)^{n_2}\\0.6=(0.85)^{n_2}

Take log both the sides as,

\log 0.6=\log (0.85)^{n_2}\\\log 0.6={n_2}\log (0.85)\\n_2=\dfrac{\log 0.6}{\log 0.85}\\n_2\approx3.14

The difference in the ages of the two cars is,

d=4.85-3.14\\d=1.71\rm years

Thus, the approximate difference in the ages of the two cars, which  depreciate to 60% of their respective original values, is 1.7 years.

Learn more about the depreciation here;

brainly.com/question/25297296

4 0
2 years ago
If you multiply a number by 3 and then subtract 5, you will get 40 what is the number
Paul [167]

Answer:

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Step-by-step explanation:

Given : If you multiply a number by 3 and then subtract 5, you will get 40.

To find : what is the number.

Solution : We have given if you multiply a number by 3 and then subtract 5, you will get 40.

According to question :

Let the number =  x

Multiply is with 3 = 3x

Subtract 5 from it we get 40 .

3x -5 = 40

On adding both sides by 5

3x = 45 .

On dividing both sides by 3

x =  15.

Therefore, Number  = 15.

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