Rolle's Theorem does not apply to the function because there are points on the interval (a,b) where f is not differentiable.
Given the function is 
and the Rolle's Theorem does not apply to the function.
Rolle's theorem is used to determine if a function is continuous and also differentiable.
The condition for Rolle's theorem to be true as:
- f(a)=f(b)
- f(x) must be continuous in [a,b].
- f(x) must be differentiable in (a,b).
To apply the Rolle’s Theorem we need to have function that is differentiable on the given open interval.
If we look closely at the given function we can see that the first derivative of the given function is:
![\begin{aligned}f(x)&=\sqrt{(2-x^{\frac{2}{3}})^3}\\ f(x)&=(2-x^{\frac{2}{3}})^{\frac{3}{2}}\\ f'(x)&=\frac{3}{2}(2-x^{\frac{2}{3}})^{\frac{1}{2}}\cdot \frac{2}{3}\cdot (-x)^{\frac{1}{3}}\\ f'(x)&=\frac{-\sqrt{2-x^{\frac{2}{3}}}}{\sqrt[3]{x}}\end](https://tex.z-dn.net/?f=%5Cbegin%7Baligned%7Df%28x%29%26%3D%5Csqrt%7B%282-x%5E%7B%5Cfrac%7B2%7D%7B3%7D%7D%29%5E3%7D%5C%5C%20f%28x%29%26%3D%282-x%5E%7B%5Cfrac%7B2%7D%7B3%7D%7D%29%5E%7B%5Cfrac%7B3%7D%7B2%7D%7D%5C%5C%20f%27%28x%29%26%3D%5Cfrac%7B3%7D%7B2%7D%282-x%5E%7B%5Cfrac%7B2%7D%7B3%7D%7D%29%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D%5Ccdot%20%5Cfrac%7B2%7D%7B3%7D%5Ccdot%20%28-x%29%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D%5C%5C%20f%27%28x%29%26%3D%5Cfrac%7B-%5Csqrt%7B2-x%5E%7B%5Cfrac%7B2%7D%7B3%7D%7D%7D%7D%7B%5Csqrt%5B3%5D%7Bx%7D%7D%5Cend)
From this point of view we can see that the given function is not defined for x=0.
Hence, all the assumptions are not satisfied we can reach a conclusion that we cannot apply the Rolle's Theorem.
Learn more about Rolle's Theorem from here brainly.com/question/12279222
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Answer:
78 rounds to 80, so find 10% of 80 and double it. 10% of 80 is 8. So, 20% of 80 is 16. Then, 22% of 78 is a little more than 16.
78 rounds to 80, and 22% is a little less than 25%. 25% (or one-fourth) of 80 is 20. So, 22% of 78 is a little less than 20.
Step-by-step explanation:
Answer:
The probability of the number of starfish dropping below 3 is 0.0463.
Step-by-step explanation:
Let X represent the number of starfish in the tide pool.
X follows a Poisson distribution with mean 6.4.
The formula for Poisson distribution is as follows.
![P(X=x) = e^{-6.4} * [6.4^{x} / x!] when x = 0, 1, ...](https://tex.z-dn.net/?f=P%28X%3Dx%29%20%3D%20e%5E%7B-6.4%7D%20%2A%20%5B6.4%5E%7Bx%7D%20%2F%20x%21%5D%20when%20x%20%3D%200%2C%201%2C%20...)
otherwise
We need to find the probability that the number of starfish in the tide pool drops below 3.
Therefore, the required probability is:
P(X < 3) = P(X = 0) + P(X = 1) + P(X=2)
P(X < 3) = 0.00166 + 0.01063 + 0.03403
P (X < 3) = 0.0463
Answer:
0.000005832 m³
Step-by-step explanation:
V = L²
= (18mm)³
= 5832 mm³
= 0.000005832 m³
Tsquare= Ksquare +Vsquare -2(K)(V) times cosT
