Question

Can someone help me with this​

Answer 1

Answer:

Step-by-step explanation:

a) -14 , -9 , -4 , 1 ................

Common difference = d = 2nd term - 1st term

           = -9-[-14]

           = -9 + 14

          d = 5

The next term can be got by adding 5 to the previous term

5th term = 1 + 5 = 6

6th term = 6 + 5 = 11

7th term = 11 + 5 = 16

Next 3 terms are : 6 , 11 , 16

$b) \frac{5}{6},\frac{2}{3},\frac{1}{2},\frac{1}{3},.....\\\\d = \frac{2}{3}-\frac{5}{6}\\\\=\frac{2*2}{3*2}-\frac{5}{6}\\\\=\frac{4}{6}-\frac{5}{6}\\\\=\frac{-1}{6}\\\\a_{5} = \frac{1}{3}+\frac{-1}{6}=\frac{1*2}{3*2}+\frac{-1}{6}=\frac{2}{6}+\frac{-1}{6}=\frac{1}{6}\\\\a_{6}=\frac{1}{6}+\frac{-1}{6}=0\\\\a_{7}=0+\frac{-1}{6}=\frac{-1}{6}\\\\\\Next 3 terms : \frac{1}{6},0,\frac{-1}{6}$