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aleksandrvk [35]
3 years ago
9

A pair of sunglasses cost $26 during the summer sale. If

Mathematics
1 answer:
Marta_Voda [28]3 years ago
7 0

Answer:2.18$

Step-by-step explanation: 26 + 7% tax is 27.82 so 30 - 27.82 = 2.18$

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The smaller triangle was dilated to form the larger triangle. What is the value of x? A smaller triangle has side lengths of 5,
riadik2000 [5.3K]

Answer:

x = 7.5

Step-by-step explanation:

Dilation is a transformation in which the size of a given figure is either increased or decreased by a scale factor.

Given that the length of sides of the smaller triangle are; 5, 13, 12.

Given also that the length of the dilated triangle are; x, blank, 18.

Comparing the length of the last sides of the two triangles, we have;

(scale factor x 12) + 12

                        = (\frac{1}{2} x 12) + 12

                        = 6 + 12

                        = 18

Thus the scale factor for the dilation is \frac{1}{2}. So that:

x = (\frac{1}{2} x 5) + 5

   = 2.5 + 5

   = 7.5

x = 7.5

And also,

blank = (\frac{1}{2} x 13) + 13

          = 6.5 + 13

blank  = 19.5

Therefore, the length of the sides of dilated triangle are: 7.5, 19.5, 18

4 0
3 years ago
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Each week, the price of oranges at the farmer's market increases by 20%. The price of oranges this week is 2.50 What was the pri
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The price last week was $2.08
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2 years ago
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A bag contains 26 letters and 9 numerals. Aubrey draws two cards from the bag. What is the probability that she draws 2 numerals
Ne4ueva [31]
The probability is 34% because 9/26=.34615384615. The first 2 numbers makes the percentage
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2 years ago
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1. Use the inequality 12≥6(12x+2).
IgorLugansk [536]

Answer: x≤0 is the answer or (−∞,0

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Step-by-step explanation:

6 0
3 years ago
Simplify f+g / f-g when f(x)= x-4 / x+9 and g(x)= x-9 / x+4
steposvetlana [31]

f(x)=\dfrac{x-4}{x+9};\ g(x)=\dfrac{x-9}{x+4}\\\\f(x)+g(x)=\dfrac{x-4}{x+9}+\dfrac{x-9}{x+4}=\dfrac{(x-4)(x+4)+(x-9)(x+9)}{(x+9)(x+4)}\\\\\text{use}\ a^2-b^2=(a-b)(a+b)\\\\=\dfrac{x^2-4^2+x^2-9^2}{(x+9)(x+4)}=\dfrac{2x^2-16-81}{(x+9)(x+4)}=\dfrac{2x^2-97}{(x+9)(x+4)}\\\\f(x)-g(x)=\dfrac{x-4}{x+9}-\dfrac{x-9}{x+4}=\dfrac{(x-4)(x+4)-(x-9)(x+9)}{(x+9)(x+4)}\\\\\text{use}\ a^2-b^2=(a-b)(a+b)\\\\=\dfrac{x^2-4^2-(x^2-9^2)}{(x+9)(x+4)}=\dfrac{x^2-16-x^2+81}{(x+9)(x+4)}=\dfrac{65}{(x+9)(x+4)}


\dfrac{f+g}{f-g}=(f+g):(f-g)=\dfrac{2x^2-97}{(x+9)(x+4)}:\dfrac{65}{(x+9)(x+4)}\\\\=\dfrac{2x^2-97}{(x+9)(x+4)}\cdot\dfrac{(x+9)(x+4)}{65}\\\\Answer:\ \boxed{\dfrac{f+g}{f-g}=\dfrac{2x^2-97}{65}}

6 0
3 years ago
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