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Debora [2.8K]
3 years ago
7

Interquantile range x^2-5x+6=0

Mathematics
1 answer:
Paul [167]3 years ago
6 0

F(x)/geq-1/4

Your welcome

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I don’t understand this and I did take notes on this on the computer but I still don’t understand it.
Serggg [28]

Answer:

<em>I</em>'[−3, −2], <em>Q</em>'[2, 0], <em>?</em>'[0, 1], <em>E</em>'[−3, −1]

Step-by-step explanation:

The line of reflection is at <em>y = −</em><em>2</em>,<em> </em>so looking at the line and where the coordinates of the shape are, you will have this:

<em>I</em>[−3, −2] → <em>I</em>'[−3, −2] (on the line, so it remains the same)

<em>Q</em>[2, −4] → <em>Q</em>'[2, 0]

<em>?</em>[0, −5] →<em> </em><em>?</em>'[0, 1]

<em>E</em>[−3, −3] → <em>E</em>'[−3, −1]

I am joyous to assist you anytime.

3 0
4 years ago
A construction worker needs to determine the volume of a sandpille in a construction yard as shown
postnew [5]
Answer:
6580cm
Step-by-step explanation:
The answer is 6580cm because....
Step one First let's figure out what the smaller shape's volume is. To do so we need to multiply ( LxWxH ) so 6x5x? it does not list what the height is so we know it has the same height as the larger shape and it's height is 14cm so we will use 14cm. 6x5x14=420cm
Step two Now lets find the Volume of the larger shape. So lets do LxWxH so Lx?x14 it does not give us the length so we need to add up all of the numbers along the line. We got 7cm then 5 from the bottom of the smaller shape and 10cm. all ads up to 22cm so 20x22x14=6160
Finally we add up the following shapes Volume which are 6160+420=6580cm
3 0
3 years ago
3. Describe the solution to the equation.
Law Incorporation [45]
I don’t really know? What grade is this?
4 0
3 years ago
Hiya Guys , Can you help me if you do one answer each Ill give you a thanks and Stars / Rating and A Brainlist , please help !!!
Volgvan

Answer:

I don't know I'm sorry I will tell you another answer asks me to

6 0
3 years ago
Trapezoid WKLX has vertices W(2, −3), K(4, −3), L(5, −2) , and X(1, −2) . Trapezoid WKLX ​ is translated 4 units right and 3 uni
IRINA_888 [86]
<span>WKLX
W(2, −3),  
K(4, −3),
L(5, −2) ,
X(1, −2) 

TRANSLATED 4 UNITS RIGHT and 3 UNITS DOWN to produce W'K'L'X

4 units right means the x coordinate is affected. Since the moving to the right, we add 4 to the x values of each vertice.

W = 2 + 4 = 6
K = 4 + 4 = 8
L = 5 + 4 = 9
X = 1 + 4 = 5

3 units down means the y axis is affected. We add 3 to the value of y but keep the negative sign.
W = -3 + -3 = -6
K = -3 + -3 = -6
L = -2 + -3 = -5
X = -2 + -3 = -5

The correct answer is: </span><span>W′(6, −6), K′(8, −6), L′(9, −5) , and X′(5, −5)</span>
6 0
4 years ago
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