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3 years ago

14

Big burgers restaurant just got a shipment of ground beef that was 384 oz they make one pound burgers how many burgers can they

make with the shipment that they received

1 answer:

Oxana [17]3 years ago

7 0

Depends how many ounces each burger is made with

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Please help!!! this is due today I will give brainliest answer

seropon [69]

IM VERY SORRY I DONT KNOW THE REAL ANSWER

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3 years ago

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Question 2 (1 point)<br> Quotient =<br><br> Find the quotient 9 =

Anarel [89]

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3

Step-by-step explanation:

9/3=3

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4 years ago

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A girl scout troop sold cookies. If the girls Sold 5 more boxes the second week than they did the first and if they doubled the

Art [367]

Since the girl scout sold 5 more boxes on the second week, we have (x + 5) number of boxes sold for the second week. Now, for the third week, since it's double that of the second week, we have 2(x + 5). Thus, we have the following:

first week: x
second week: x + 5
third week: 2(x + 5)

Given that the total number of boxes sold for the three weeks is 431. We have

x + (x + 5) + 2(x + 5) = 431
x + x + 5 + 2x + 10 = 431
4x + 15 = 431
4x = 431 - 15
4x = 416
x = 104

We have now the value of x. Using this, we can find the values for the second and third week.
x + 5 = `104 + 5 = 109
2(x + 5) = 2(109) = 218

Answer:
first week: 104
second week: 109
third week: 218

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3 years ago

Solve the system of linear equations by elimination.

aleksley [76]

Answer:

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3 years ago

14. A company uses many different delivery

ziro4ka [17]

Answer:

0.6603 = 66.03% probability that it will be sent with the ABC Speedy Delivery Company and arrive on time.

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Sent by ABC Speedy Delivery Service.

Event B: Arrived on time.

The probability that any given parcel will be sent by the ABC Speedy Delivery Service is 0.71.

This means that $P(A) = 0.71$

The probability that the parcel will arrive on time given the ABC Speedy Delivery Company was used is 0.93.

This means that $P(B|A) = 0.93$

Find the probability that it will be sent with the ABC Speedy Delivery Company and arrive on time.

This is $P(A \cap B)$ . So

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

$P(A \cap B) = P(B|A)*P(A) = 0.93*0.71 = 0.6603$

0.6603 = 66.03% probability that it will be sent with the ABC Speedy Delivery Company and arrive on time.

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3 years ago