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Stells [14]
4 years ago
10

Which statement is not true of the given diagram?​

Mathematics
1 answer:
Margaret [11]4 years ago
5 0
D
Explanation:

a: a straight line is 180* and angle 2 and 3 does equal and equal line so that one is true.

b: same with answer a, 4 and 2 make a straight line so it would equal 180*

c: 3 and 4 are vertical angles bc they are a pair of opposite angles on intersecting lines.

d: i ruled out the answers, so D has to be the answer

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9x-4=5x+6<br><img src="https://tex.z-dn.net/?f=9x%20-%204%20%3D%205x%20%2B%206" id="TexFormula1" title="9x - 4 = 5x + 6" alt="9x
wlad13 [49]
9x-4=5x-6
    +4    +4
 9x=5x-2
-5x-5x

4x=-2
divide by 2 on both sides
x=-2 or
x= 4/9
7 0
4 years ago
(5,2), (-2,5),(2,5),(-5,2)
Alecsey [184]

Answer:

the second row is not a function! top row is a function

Step-by-step explanation:

because in order for it to be a function for every x there is exactly one y meaning there is no repeating x values! the second row had x = 5 twice, therefore they repeated x values meaning it's not a function

6 0
3 years ago
Which expression is equivalent to 10i/2-1?
stellarik [79]
Your answer is 4.....

7 0
3 years ago
PLEASE HELP<br> 7x-3= -24 what is x and how do you find it?
NeX [460]

Answer:

x = -3

Step-by-step explanation:

7x - 3 = -24 (Given)

7x - 3 + 3 = -24 + 3 (Added 3 on both sides by using the addition property of equality)

7x = -21 (Simplified)

7x/7 = -21/7 (Divided 7 on both sides by using the division property of equality)

x = -3 (Simplified)

Therefore, x = -3.

7 0
3 years ago
Read 2 more answers
Proof that :<br><img src="https://tex.z-dn.net/?f=%20%7Bsin%7D%5E%7B2%7D%20%5Ctheta%20%2B%20%20%7Bcos%7D%5E%7B2%7D%20%5C%3A%5Cth
Arisa [49]

Answer:

Solution given:

Right angled triangle ABC is drawn where <C=\theta

we know that

\displaystyle Sin\theta=\frac{opposite}{hypotenuse} =\frac{AB}{AC}

\displaystyle Cos\theta=\frac{adjacent}{hypotenuse}=\frac{BC}{AC}

Now

left hand side

\displaystyle {sin}^{2} \theta + {cos}^{2} \:\theta

Substituting value

(\frac{AB}{AC})²+(\frac{BC}{AC})²

distributing power

\frac{AB²}{AC²}+\frac{BC²}{AC²}

Taking L.C.M

\displaystyle \frac{AB²+BC²}{AC²}....[I]

In ∆ABC By using Pythagoras law we get

\boxed{\green{\bold{Opposite²+adjacent²=hypotenuse²}}}

AB²+BC²=AC²

Substituting value of AB²+BC² in equation [I]

we get

\displaystyle \frac{AC²}{AC²}

=1

Right hand side

<h3><u>proved</u></h3>

8 0
3 years ago
Read 2 more answers
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