The algebraic expression of "Four more than the quotient of a number and 3 is 9" is 
The value of x=15
Step-by-step explanation:
We need to express "Four more than the quotient of a number and 3 is 9" as algebraic expression.
Let the number = x
Solving:
quotient of a number and 3: 
Four more than the quotient of a number and 3: 
Four more than the quotient of a number and 3 is 9:
Now, finding value of x:
So, value of x = 15
Keywords: Algebraic expression
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Answer:
Final answer is ![\sqrt[3]{x^1}\cdot\sqrt[3]{x^2}=x](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%5E1%7D%5Ccdot%5Csqrt%5B3%5D%7Bx%5E2%7D%3Dx)
.
Step-by-step explanation:
Given problem is ![\sqrt[3]{x}\cdot\sqrt[3]{x^2}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%7D%5Ccdot%5Csqrt%5B3%5D%7Bx%5E2%7D)
.
Now we need to simplify this problem.
![\sqrt[3]{x^1}\cdot\sqrt[3]{x^2}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%5E1%7D%5Ccdot%5Csqrt%5B3%5D%7Bx%5E2%7D)
Apply formula
![\sqrt[n]{x^p}\cdot\sqrt[n]{x^q}=\sqrt[n]{x^{p+q}}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Bx%5Ep%7D%5Ccdot%5Csqrt%5Bn%5D%7Bx%5Eq%7D%3D%5Csqrt%5Bn%5D%7Bx%5E%7Bp%2Bq%7D%7D)
so we get:
![\sqrt[3]{x^1}\cdot\sqrt[3]{x^2}=\sqrt[3]{x^{1+2}}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%5E1%7D%5Ccdot%5Csqrt%5B3%5D%7Bx%5E2%7D%3D%5Csqrt%5B3%5D%7Bx%5E%7B1%2B2%7D%7D)
![\sqrt[3]{x^1}\cdot\sqrt[3]{x^2}=\sqrt[3]{x^{3}}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%5E1%7D%5Ccdot%5Csqrt%5B3%5D%7Bx%5E2%7D%3D%5Csqrt%5B3%5D%7Bx%5E%7B3%7D%7D)
Hence final answer is .
Range should be (-∞ , 10]
answer is C.
A plumber worked 26 hours a week for half a year. If his hourly wage was $40, how much did he earn during this time period?
<span> <span>A.</span>$1040</span><span> <span>B.</span>$27,040</span><span> <span>C.</span>$54,080</span><span> <span>D.</span><span>$520</span></span>
-2 (x+1)= -8x+1
-2x-2= -8x+1
+2x. +2x
-2= -6x+1
-1. -1
-3= -6x
÷-6
x=.5
X=0.5
