For Data Set B, we see that the data is more varied. The absolute deviations are 4, 3, 2, 5. The average of these absolute deviations is 3.5. MAD_B = (4+3+2+5)/4 =3.5 M ADB
Hence, The average of these absolute deviations is 3.5.
Answer:
t= -2.5
Step-by-step explanation:
2t−5=−10
add 5 to both sides
2t= -5
divide by 2
t= -2.5
Answer:
1=87°
2=93°
Step-by-step explanation:
angle 1 is the alternate interior angle of 87
angle 1 and angle 2 are supplementary angles
180-87=93
hopefully this helps :)
400 divided by 5 = 80.
Needs to bag at least 80.
If the position at time <em>t</em> is
<em>s(t)</em> = (1 m/s³) <em>t</em> ³
then the average velocity over <em>t</em> = 2 s and <em>t</em> = 2.001 s is
<em>v</em> (ave) = (<em>s</em> (2.001 s) - <em>s</em> (2 s)) / (2.001 s - 2 s)
<em>v</em> (ave) = ((1 m/s³) (2.001 s)³ - (1 m/s³) (2 s)³) / (2.001 s - 2 s)
<em>v</em> (ave) ≈ (8.01201 m - 8 m) / (0.001 s)
<em>v</em> (ave) ≈ 12.006 m/s
