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professor190 [17]
2 years ago
8

Two data sets have the same mean,

Mathematics
1 answer:
nirvana33 [79]2 years ago
5 0

For Data Set B, we see that the data is more varied. The absolute deviations are 4, 3, 2, 5. The average of these absolute deviations is 3.5. MAD_B = (4+3+2+5)/4 =3.5 M ADB

Hence, The average of these absolute deviations is 3.5.

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What is 2-2 equals to ?
Nikitich [7]

Answer:

The answer is 0

Step-by-step explanation:

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2 years ago
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Four friends are going to split the cost of a pizza. If p stands for the cost of the pizza, which of the following expressions c
Natasha2012 [34]

Answer: A

Step-by-step explanation:

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3 years ago
John runs a computer software store. Yesterday he counted 123 people who walked by the store, 56 of whom came into the store. Of
vaieri [72.5K]

Answer:

a) There is a 45.53% probability that a person who walks by the store will enter the store.

b) There is a 41.07% probability that a person who walks into the store will buy something.

c) There is a 18.70% probability that a person who walks by the store will come in and buy something.

d) There is a 58.93% probability that a person who comes into the store will buy nothing.

Step-by-step explanation:

This a probability problem.

The probability formula is given by:

P = \frac{D}{T}

In which P is the probability, D is the number of desired outcomes and T is the number of total outcomes.

The problem states that:

123 people walked by the store.

56 people came into the store.

23 bought something in the store.

(a) Estimate the probability that a person who walks by the store will enter the store.

123 people walked by the store and 56 entered the store, so T = 123, D = 56.

So

P = \frac{D}{T} = \frac{56}{123} = 0.4553

There is a 45.53% probability that a person who walks by the store will enter the store.

(b) Estimate the probability that a person who walks into the store will buy something.

56 people came into the store and 23 bought something, so T = 56, D = 23.

So

P = \frac{D}{T} = \frac{23}{56} = 0.4107

There is a 41.07% probability that a person who walks into the store will buy something.

(c) Estimate the probability that a person who walks by the store will come in and buy something.

123 people walked by the store and 23 came in and bought something, so T = 123, D = 23.

So

P = \frac{D}{T} = \frac{23}{123} = 0.1870

There is a 18.70% probability that a person who walks by the store will come in and buy something.

(d) Estimate the probability that a person who comes into the store will buy nothing.

Of the 56 people whom came into the store, 23 bought something. This means that 56-23 = 33 of them did not buy anything. So:

D = 33, T = 56

P = \frac{D}{T} = \frac{33}{56} = 0.5893

There is a 58.93% probability that a person who comes into the store will buy nothing.

8 0
3 years ago
Math help please (80 points)
Inga [223]

Answer:

1. x^4 -x^3 -4x^2 -3

a1 = -7.4

an = an-1 -13.8  (choice 1)

Step-by-step explanation:

f(x) = x^4 -x^2 +9

g(x) = x^3 +3x^2 +12

We are subtracting

f(x) -g(x) =x^4 -x^2 +9 - ( x^3 +3x^2 +12)

Distribute the minus sign

x^4 -x^2 +9 -  x^3 -3x^2 -12

I like to line them up vertically

x^4      -x^2 +9

-  x^3 -3x^2 -12

-------------------------

x^4 -x^3 -4x^2 -3


2.  a1 = -7.4

To find the common difference, take term 2 and subtract term 1

-21.2 - (-7.4)

-21.2 + 7.4

-13.8

an = an-1 -13.8

5 0
3 years ago
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A village wishes to measure the quantity of water that is piped to a factory during a typical morning. A gauge on the water line
anzhelika [568]

Answer:

570 m³

Step-by-step explanation:

The volume of water is the product of flow rate of water and the time taken. We are to get the volume of water used between 6 am and 9 am, that is for 3 hours (9 - 6).

We are given the flow rate at 6 am and the flow rate at 9 am, but this flow rate changes between 6 am and 9 am. To get the estimate of the water used, Let us assume that it flows at the same flow rate as it was at 6 am throughout, hence:

V_L= 100 m^3/h * 3h=300\ m^3

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To get the best estimate of the total volume, let us find the average of the two values, hence:

Volume=\frac{V_L+V_R}{2} =\frac{300+840}{2}=570\ m^3

3 0
3 years ago
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