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german
3 years ago
6

The mean of 4 8 9 x and 2x is 6 calculate the value of x

Mathematics
1 answer:
Paul [167]3 years ago
7 0

Answer:

x = 3

Step-by-step explanation:

Mathematically, the mean is the sum of the numbers divided by the count of the numbers

The count of the numbers is 5

Thus;

( 4 + 8 + 9 + x + 2x)/5 = 6

(21 + 3x)/5 = 6

21 + 3x = 6(5)

21 + 3x = 30

3x = 30-21

3x = 9

x = 9/3

x = 3

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A screening test for a disease shows a positive result in 91% of all cases when the disease is actually present and in 7% of all
Jobisdone [24]

Answer:

0.0713 = 7.13% probability that the result is positive.

Step-by-step explanation:

Probability of a positive test:

91% of 1/650(has the disease).

7% of 1 - 1/650 = 649/650(does not have the disease). So

p = 0.91\frac{1}{650} + 0.07\frac{649}{650} = \frac{0.91 + 0.07*649}{650} = 0.0713

0.0713 = 7.13% probability that the result is positive.

4 0
2 years ago
How do I solve 0.6(-13k-12)
Anton [14]

Answer:

-7.8k - 7.2

Step-by-step explanation:

Distribute 0.6 to the terms in the parentheses:

0.6(-13k - 12)

-7.8k - 7.2

So, the simplified expression is -7.8k - 7.2

4 0
3 years ago
Read 2 more answers
I NEED HELP PLEASE! ;0
Fittoniya [83]

Answer:

4:6 or 2:3

Step-by-step explanation:

Since the ratio of mass of oxygen to carbon is 4:3, when there are two carbons the ratio will be 4:3*2=4:6=2:3. Hope this helps!

8 0
3 years ago
How would you divide 0.294/3?
Arte-miy333 [17]
0.294:3= \frac{\big{294}}{\big{1000}} \cdot  \frac{\big{1}}{\big{3}} = \frac{\big{2\cdot3\cdot49}}{\big{2\cdot500}} \cdot  \frac{\big{1}}{\big{3}} = \frac{\big{49}}{\big{500}} \\\\\\0.294:3=(0.098\cdot3):3=0.098
7 0
3 years ago
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What changes would you make in your description of point, line, and plane?
weeeeeb [17]

Answer:

Here's a quick sketch of how to calculate the distance from a point P=(x1,y1,z1)

P

=

(

x

1

,

y

1

,

z

1

)

to a plane determined by normal vector N=(A,B,C)

N

=

(

A

,

B

,

C

)

and point Q=(x0,y0,z0)

Q

=

(

x

0

,

y

0

,

z

0

)

. The equation for the plane determined by N

N

and Q

Q

is A(x−x0)+B(y−y0)+C(z−z0)=0

A

(

x

−

x

0

)

+

B

(

y

−

y

0

)

+

C

(

z

−

z

0

)

=

0

, which we could write as Ax+By+Cz+D=0

A

x

+

B

y

+

C

z

+

D

=

0

, where D=−Ax0−By0−Cz0

D

=

−

A

x

0

−

B

y

0

−

C

z

0

.

This applet demonstrates the setup of the problem and the method we will use to derive a formula for the distance from the plane to the point P

P

.

Step-by-step explanation:

5 0
3 years ago
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