The mode is the number that appears the most times, like if you had a set of numbers, for example {1,6,6,8,8,8,8,8,10,12,14}, the mode would be 8, since it appeared the most, do the same for that table, which wasn't provided for me to see.
<em>Look</em><em> </em><em>at</em><em> </em><em>the</em><em> </em><em>attached</em><em> </em><em>picture</em><em> </em><em>⤴</em>
<em>Hope</em><em> </em><em>this</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>u</em><em>.</em><em>.</em><em>.</em><em>:</em><em>)</em>
Answer:
the number of non-farm jobs started going down in 2008
Step-by-step explanation:
The question presented requires the analysis and interpretation of graphical output of data.
From the graph it is true to say that the number of non-farm jobs did not remain consistent over time since the graph is moving down then up implying decrease followed by increase.
It is also true to say that the number of non-farm jobs started going up in 2010 as indicated by the upward trend of the graph.
From 2008 to around 2010 the graph is moving downwards suggesting that the number of non-farm jobs was declining.
Answer:
The degrees of freedom are given by:
Now we can calculate the p value with the following probability:
And for this case since the p value is lower compared to the significance level we can reject the null hypothesis and we can conclude that the true mean for this case is different from 30.6 at the significance level of 0.05
Step-by-step explanation:
For this case we have the following info given:
represent the sample mean
represent the sample deviation
represent the reference value to test.
represent the sample size selected
The statistic for this case is given by:
And replacing we got:
The degrees of freedom are given by:
Now we can calculate the p value with the following probability:
And for this case since the p value is lower compared to the significance level we can reject the null hypothesis and we can conclude that the true mean for this case is different from 30.6 at the significance level of 0.05