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alukav5142 [94]
3 years ago
9

What is an explicit formula for the following sequence 1,5,9,13,17 ? plssss helppp mee

Mathematics
1 answer:
morpeh [17]3 years ago
7 0

Answer:

plus 4 every time

Step-by-step explanation:

1+4=5+4=9+4=13+4=17

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Q7Which statement is incorrect for the graph of thefunction y = -5 cosGcos( 3 (x – 3)) +62The period is 4.The amplitude is 3.The
guajiro [1.7K]

The given function is,

y=-5\cos (\frac{\pi}{2}(x-3))+6

The graph can be drawn as,

The period will be distance between two consequetive maximas,

\text{Period}=1-(-3)=4

Thus, period is correct.

The amplitude can be determined as,

\begin{gathered} Amplitude=\frac{\max -\min }{2} \\ =\frac{11-1}{2} \\ =5 \end{gathered}

Thus, amplitue is incorrect.

The range is,

y\in\lbrack1,11\rbrack

Thus, the range is correct.

The midline is,

\begin{gathered} \text{midline}=\frac{\max +\min }{2} \\ =\frac{1+11}{2} \\ =6 \end{gathered}

Thus, the midline is correct.

Thus, option (b) is the solution.

5 0
1 year ago
HELP PLEASE THIS IS DUE IN 30 MIN PLEASE HELP URGENT
Oxana [17]

Answer:

12.5

Step-by-step explanation:

3 0
3 years ago
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Answer right with proof please.
Diano4ka-milaya [45]

Answer:

the answer is a

Step-by-step explanation:

you times the 1/6 by 2 to get 2/12 then 3/4 by 3 to get 9/12 so all your fractions have the same denominator and the do the rest of the math with the new fractions and the same whole numbers that went with them. hope this helps

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3 years ago
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The height, h, in feet of a rock above the ground is given by the equation h = -16t^2 + 24t + 16, where t is the time in seconds
boyakko [2]

The rock will hit the ground at 2 seconds.

Explanation:

Given that the height, h, in feet of a rock above the ground is given by the equation h=-16t^2+24t+16, where t is the time in seconds after the rock is thrown.

We need to determine the time at which the rock will hit the ground.

To determine the time, let us equate the height h = 0 in the equation h=-16t^2+24t+16, we get,

0=-16t^2+24t+16

Switch sides, we have,

-16 t^{2}+24 t+16=0

Let us solve the equation using the quadratic formula.

Thus, we have,

t=\frac{-24 \pm \sqrt{24^{2}-4(-16) 16}}{2(-16)}

Simplifying, we get,

t=\frac{-24 \pm \sqrt{576+1024}}{-32}

t=\frac{-24 \pm \sqrt{1600}}{-32}

t=\frac{-24 \pm 40}{-32}

Hence, the two values of t are

t=\frac{-24 + 40}{-32}   and   t=\frac{-24 -40}{-32}

Simplifying the values, we get,

t=\frac{16}{-32}  and  t=\frac{-64}{-32}

Dividing, we get,

t=-\frac{1}{2}  and  t=2

Since, t cannot negative values, we have,

t=2

Thus, the rock will hit the ground at 2 seconds.

8 0
3 years ago
A new bank account is opened on week 1 with a $200 deposit. After that first week, weekly deposits of $55 are made in the accoun
inysia [295]
Y=55x+200, you multiply the number of weeks by the amount of money, and add 200 because they started with that.   
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