Answer:
-5/2(3x+4)<6-3x (multiply with -5/2)
-15/2x-10<6-3x (multiply with 2)
-15x-20<12-6x (change sides)
-15x+6x<12+20
-9x<12+20
-9x<32
x>-32/9
Hope this will help u :)
-5
u can rearrange it to be y = -5x + 3
Step-by-step explanation:
Remember:
SOH - Sin(angle) = Opposite/Hypotenuse
CAH - Cos(angle) = Adjacent/Hypotenuse
TOA - Tan(angle) = Opposite/Adjacent
Answer:
The half-life of the radioactive substance is of 3.25 days.
Step-by-step explanation:
The amount of radioactive substance is proportional to the number of counts per minute:
This means that the amount is given by the following differential equation:

In which k is the decay rate.
The solution is:

In which Q(0) is the initial amount:
8000 counts per minute on a Geiger counter at a certain time
This means that 
500 counts per minute 13 days later.
This means that
. We use this to find k.







So

Determine the half-life of the radioactive substance.
This is t for which Q(t) = 0.5Q(0). So







The half-life of the radioactive substance is of 3.25 days.
The original number is .9