What is the median of the data below?<br><br>
45, 19, 23, 67, 28, 35, 46, 21, 58, 60, 23, 51
VLD [36.1K]
To find the median, you will need to list the data from least to greatest and find the middle number.
19, 21, 23, 23, 28, 35, 45, 46, 51, 58, 60, 67
Cross out a number on both sides until you reach the middle number. In this case, we are left with 2 numbers that are in the middle since there is an even amount of numbers.
When you reach the time where you have two middle numbers, we have to find the average of those two numbers. Our two middle numbers are 35 and 45. Since we have to find the average of those two numbers, we can add them. (35 + 45 = 80). Now, since we have two middle numbers, we have to divide them by 2.

Answer:
Answer:
The upper limit of the 95% confidence interval is:
C.I_u = 200 + (58.8/
)
Step-by-step explanation:
The formula is given as:
C.I = μ ± Z*σ/
The upper limit => C.I_u = μ + Z*σ/
The lower limit => C.I_l = μ - Z*σ/
The sample size (n) is not stated in the question. Hence, we calculate the upper limit with respect to n.
The upper limit => C.I_u = 200 + 1.96*(30/
)
= 200 + (1.96*30)/
= 200 + 58.8/
9514 1404 393
Answer:
a ≈ 4.68
Step-by-step explanation:
The law of cosines tells you ...
a² = b² +c² -2bc·cos(A)
a = √(b² +c² -2bc·cos(A))
a = √(5² +8² -2·5·8·cos(33°)) = √(25 +64 -80·0.83867) ≈ √21.906
a ≈ 4.68
Answer:
que que
Step-by-step explanation:
que
Answer:
30
Step-by-step explanation:
3 pieces each 1 dekameter long
1 dekameter = 10 meters
Convert dekameters to meters
3 pieces each 10 meters long
Multiply
Glenn has 30 meters of lanyard
Divide
He can cut 30 1-meter pieces
Hope this helps :)