Given the function f (x) = 3x, find the value of f-1 (81).
For this case, the first thing you should do is rewrite the function.
We have then:
y = 3 ^ x
From here, we clear the value of x:
log3 (y) = log3 (3 ^ x)
log3 (y) = x
Then, we rewrite the function again:
f (x) ^ - 1 = log3 (x)
Now, we evaluate the inverse function for x = 81:
f (81) ^ - 1 = log3 (81)
f (x) ^ - 1 = 4
Answer:
the value of f-1 (81) is:
f (x) ^ - 1 = 4
You add them and then divide by how many numbers there are.
a. (3+43)/2 = 23
b. 0
c. -1
Answer: The first number that appears in both sequences is 28.
Step-by-step explanation:
Let's write down numbers from each of the sequences
Sequence 1) We need to start from 7 and multiply 4
7x4=28, 28x4=112
The sequence is 7,28,112...
Sequence 2) We need to start from 8 and add 5
5+8=13, 13+5=18, 18+5=23, 23+5=28
The sequence is 8,13,18,23,28...
They both have 28
Option 3: a 90 degree rotation clockwise
You can tell that it is 90 degrees because the original started completely in quadrant 2 and the final image is completely in quadrant 1. If it was only rotated 45 degrees the final image would be part in quadrant 2 and part in quadrant 1. It was rotated clockwise because that is the way a clock goes.
Hope this helps! ;)
