-x^2+105x-1050=1550
We move all terms to the left:
-x^2+105x-1050-(1550)=0
We add all the numbers together, and all the variables
-1x^2+105x-2600=0
a = -1; b = 105; c = -2600;
Δ = b2-4ac
Δ = 1052-4·(-1)·(-2600)
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
<span><span>x1</span>=<span><span>−b−<span>Δ√</span></span><span>2a</span></span></span><span><span>x2</span>=<span><span>−b+<span>Δ√</span></span><span>2a</span></span></span>
<span><span>Δ<span>−−</span>√</span>=<span>625<span>−−−</span>√</span>=25</span>
<span><span>x1</span>=<span><span>−b−<span>Δ√</span></span><span>2a</span></span>=<span><span>−(105)−25</span><span>2∗−1</span></span>=<span><span>−130</span><span>−2</span></span>=+65</span>
<span><span><span>x2</span>=<span><span>−b+<span>Δ√</span></span><span>2a</span></span>=<span><span>−(105)+25</span><span>2∗−1</span></span>=<span><span>−80</span><span>−2</span></span>=+40</span></span>
Answer:
As you should
Step-by-step explanation:
Answer:
Given : The linear function f(x) = 0.2x + 79 represents the average test score in math class, where x is the number of the test taken.
The linear function g(x) represents the average test score in your science class, where x is the number of the test taken.
X
g(x)
1 1
86
2 3
84
82
To Find : test average for math class after completing test 2
test average for science class after completing test 2
Which class had a higher average after
completing test
Solution:
f(x) = 0.2x + 79
=> f/2) = 0.212) + 79 = 79.4f(x) = 0.2x + 79
=> f(4) = 0.2(4) + 79 = 79.8
test average for math class after completing test 4 = 79.8 =
1 1 2 3 4 g(x) 86 84 82 80
Х
g(2) = 84
test average for science class after completing test 2 = 84
g(4) = 80
test average for science class after completing test 4 = 80
80 > 79.8science class has more average than
MARK AS THE BRAINLIEST
math after 4 test
The answer is b if you do the equation right
Answer:
<h2>D. y - 5 = 2/3(x + 3)</h2>
Step-by-step explanation:
The point-slope form of an equation of a line:
We have the slope 2/3 an the point (-3, 5). Substitute:
