Taiga’s teacher asked him to draw a polygon with vertices (–4, –5), (–5, 2), (–5, 3), (–4, 5), (2, 3), and (–3, 0) and to identi
fy the polygon. Taiga drew the polygon below and identified it as a heptagon.
Which explains whether Taiga is correct?
Taiga is correct because the polygon has six sides.
Taiga is correct because the sides have different lengths.
Taiga is not correct because the polygon is a hexagon.
Taiga is not correct because he drew the polygon incorrectly.
Which explains whether Taiga is correct?
Taiga is correct because the polygon has six sides.
Taiga is correct because the sides have different lengths.
Taiga is not correct because the polygon is a hexagon.
Taiga is not correct because he drew the polygon incorrectly.
1 answer:
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Answer:
It is not normally distributed as it has it main concentration in only one side.
Step-by-step explanation:
So, we are given that the class width is equal to 0.2. Thus we will have that the first class is 0.00 - 0.20, second class is 0.20 - 0.40 and so on(that is 0.2 difference).
So, let us begin the groupings into their different classes, shall we?
Data given:
0.31 0.31 0 0 0 0.19 0.19 0 0.150.15 0 0.01 0.01 0.19 0.19 0.53 0.53 0 0.
(1). 0.00 - 0.20: there are 15 values that falls into this category. That is 0 0 0 0.19 0.19 0 0.15 0.15 0 0.01 0.01 0.19 0.19 0 0.
(2). 0.20 - 0.40: there are 2 values that falls into this category. That is 0.31 0.31
(3). 0.4 - 0.6 : there are 2 values that falls into this category.
(4). 0.6 - 0.8: there 0 values that falls into this category. That is 0.53 0.53.
Class interval frequency.
0.00 - 0.20. 15.
0.20 - 0.40. 2.
0.4 - 0.6. 2.
