P(B) = 8/12
P(R | B) = 4/11
P(B ∩ R) = 8/33
The probability that the first ball chosen is black and the second ball chosen is red is about 24% percent
<em><u>Solution:</u></em>
<em><u>The probability is given as:</u></em>

Given that,
A box contains four red balls and eight black balls
Red = 4
Black = 8
Total number of possible outcomes = 12
Let event B be choosing a black ball first and event R be choosing a red ball second.
<h3><u>Find P(B)</u></h3>

<h3><u>Find P(B n R)</u></h3>

<h3><u>Find </u><u>
P(R | B)</u></h3><h3>

</h3>
<em><u>The probability that the first ball chosen is black and the second ball chosen is red is about percent</u></em>

Thus the probability that the first ball chosen is black and the second ball chosen is red is about 24% percent
Answer:
1
Step-by-step explanation:
1 goes into both
Answer:
Law of Sines, two sides and an opposite angle are known
Step-by-step explanation:
We are given <R, which is an opposite angle to side r.
Side q is also given, which has an unknown opposite angle, <Q, of which we are required to find.
Since two sides and an opposite angle are known, The Law of Sines would be applied in solving for <Q.
Thus, the following would be used:

1.63636363636363636363636363636.........
Step-by-step explanation:
2x + 8 = 4x + 3 - 2x + 5
2x - 4x + 2x = 3 +5 -8
0 = 0
x = 0