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3 years ago

On a coordinate grid, where is the center of this circle?

Mathematics

1 answer:

lisabon 2012 [21]3 years ago

8 0

Answer:

Option B) (0,0) is the correct answer.

Step-by-step explanation:

Given equation of circle is:

$x^2+y^2 = 2$

The general form of equation of circle with center at (h,k) and radius r is given by:

$(x-h)^2+(y-k)^2 = r^2$

The given equation of circle can also be written as:

$(x-0)^2+(y-0)^2 = 2$

Comparing it with the general form of equation, we get

h = 0 , k = 0

So the center is (0,0)

Hence,

Option B) (0,0) is the correct answer.

You might be interested in

If you had half a dollar, three quarters, eight dimes, six nickels, and nine pennies, how much money would you have altogether?

hjlf

Answer:

$1.69

Step-by-step explanation:

Half a dollar = $0.50

Eight dimes = $0.80

Six nickels = $0.30

Nine pennies = $0.09

Total = $0.50 + $0.80 + $0.30 + $0.09 = $1.69

4 0

3 years ago

If a truck weighs 3 1/2 tons, how many pounds does it weigh?

Gennadij [26K]

1 ton is 2000 pounds your answer is 7000 pounds

Hope this helps

4 0

3 years ago

In the xy-plane, if line k has negative slope and passes through the point (−5,r), is the x-intercept of line k positive?

aksik [14]

We Need more info please us at brainly would like you to provide more information so we can answer your question right away thank you have a goodnight.

7 0

4 years ago

At the start of the year, 15 chameleons were introduced into a zoo. The population of chameleons is expected to grow at a rate o

bearhunter [10]

Answer:

option-B

Step-by-step explanation:

We are given

At the start of the year, 15 chameleons were introduced into a zoo

so, $P_0=15$

The population of chameleons is expected to grow at a rate of 41.42% every year

so, r=0.4142

and x represents the number of years since the chameleons were introduced into the zoo

now, we can set equation to find total population

and we get

$P(x)=P_0(1+r)^x$

now, we can plug values

$P(x)=15(1+0.4142)^x$

$P(x)=15(1.4142)^x$

Average rate of change between 2 years and 4 years:

we can use formula

$A_1=\frac{P(4)-P(2)}{4-2}$

now, we can plug values

$A_1=\frac{15(1.4142)^{4}-15(1.4142)^{2}}{4-2}$

$A_1=14.99914$

Average rate of change between 4 years and 6 years:

we can use formula

$A_2=\frac{P(6)-P(4)}{6-4}$

now, we can plug values

$A_2=\frac{15(1.4142)^{6}-15(1.4142)^{4}}{6-4}$

$A_2=29.99770$

Average rate of change between 6 years and 8 years:

we can use formula

$A_3=\frac{P(8)-P(6)}{8-6}$

now, we can plug values

$A_3=\frac{15(1.4142)^{8}-15(1.4142)^{6}}{8-6}$

$A_3=59.99425$

now, we will check each options

option-A:

we can see that

$A_3-A_2=30$

So, this is FALSE

option-B:

$A_1=\frac{1}{2}A_2$

So, this is TRUE

option-C:

This is FALSE

option-D:

we got

$A_1=\frac{1}{2}A_2$

so, this is FALSE

5 0

3 years ago

More free points just say thanks!

balu736 [363]

Answer:

Thank you

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers