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Delvig [45]
3 years ago
5

19/24= how many pounds

Mathematics
1 answer:
WINSTONCH [101]3 years ago
7 0
Is the problem 19÷24?
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3 years ago
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The standard form of the equation of a circle is (x−5)2+(y−6)2=1.
Crank

Answer:

(A)x^2+y^2-10x-12y+60=0

Step-by-step explanation:

The standard form of the equation of a circle is given as:

(x-5)^2+(y-6)^2=1

Simplifying the above given equation, we get

x^2+25-10x+y^2+36-12y=1

x^2+y^2-10x-12y+36+25=1

x^2+y^2-10x-12y+61=1

x^2+y^2-10x-12y+60=0

which is the required general form of the equation.

Hence, option A is correct.

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4 years ago
What types of erosion creates caves?
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4 0
3 years ago
Please please someone help
natka813 [3]

The answer is the first one:

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How many positive integers $n$ from 1 to 5000 satisfy the congruence $n \equiv 5 \pmod{12}$?
irga5000 [103]
The equivalence n \equiv 5 \pmod{12}

means that n-5 is a multiple of 12.

that is

n-5=12k, for some integer k

and so

n=12k+5


for k=-1, n=-12+5=-7

for k= 0, n=0+5=5 (the first positive integer n, is for k=0)


we solve 5000=12k+5 to find the last k

12k=5000-5=4995

k=4995/12=416.25

so check k = 415, 416, 417 to be sure we have the right k:

n=12k+5=12*415+5=4985

n=12k+5=12*416+5=4997

n=12k+5=12*417+5=5009


The last k which produces n<5000 is 416


For all k∈{0, 1, 2, 3, ....416}, n is a positive integer from 1 to 5000,

thus there are 417 integers n satisfying the congruence.


Answer: 417

6 0
4 years ago
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