Solve plz 500 - 2.23

Mathematics

2 answers:

Strike441 [17]2 years ago

7 0

Answer:

497.8

Step-by-step explanation:

500-2.23=497.77=497.8

GenaCL600 [577]2 years ago

7 0

Answer:

500-2.23

500-2.23
497.77

hope it helps

<h3>stay safe healthy and happy.</h3>

You might be interested in

A store sells tea cups in sets of 9 and saucers in sets of 12. The store sold the same number of individual cups and saucers in

BlackZzzverrR [31]

The first five multiples of 9 are 9 18 27 36 45 I hope that's what you mean.

The prime factors of 9 and 12 are

9: 3 * 3

12: 3 * 2 * 2

The LCM is 3*3*2*2 is 36

The store sold 4 sets of cups ans 3 sets saucers. Answer

6 0

3 years ago

A simple random sample of size nequals10 is obtained from a population with muequals68 and sigmaequals15. (a) What must be true

valentina_108 [34]

Answer:

(a) The distribution of the sample mean ( $\bar x$ ) is N (68, 4.74²).

(b) The value of $P(\bar X$ is 0.7642.

Step-by-step explanation:

A random sample of size n = 10 is selected from a population.

Let the population be made up of the random variable X.

The mean and standard deviation of X are:

$\mu=68\\\sigma=15$

(a)

According to the Central Limit Theorem if we have a population with mean μ and standard deviation σ and we take appropriately huge random samples (n ≥ 30) from the population with replacement, then the distribution of the sample mean will be approximately normally distributed.

Since the sample selected is not large, i.e. n = 10 < 30, for the distribution of the sample mean will be approximately normally distributed, the population from which the sample is selected must be normally distributed.

Then, the mean of the distribution of the sample mean is given by,

$\mu_{\bar x}=\mu=68$