The increase from 5 to 8 was by 60%.
Answer:
B. x ≈ 13/8
Step-by-step explanation:
We assume that one iteration consists of determining the midpoint of the interval known to contain the root.
The graph shows the functions intersect between x=1 and x=2, hence our first guess is x = 3/2.
Evaluation of the difference between the left side expression and the right side expression for x = 3/2 shows that difference to be negative, so we can narrow the interval to (3/2, 2). Our 2nd guess is the midpoint of this interval, so is x = 7/4.
Evaluation of the difference between the left side expression and the right side expression for x = 3/4 shows that difference to be positive, so we can narrow the interval to (3/2, 7/4). Our 3rd guess is the midpoint of this interval, so is x = 13/8.
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The sign of the difference at this value of x is still negative, so the next guess would be 27/16. It is a little hard to tell what the question means by "3 iterations." Evaluating the function for x=13/8 will be the third evaluation, so the determination that x=27/16 will be the next guess might be considered to be the result of the 3rd iteration.
Answer:

Step-by-step explanation:
From the question we are told that
Matrix is given as 
Generally let the change in matrix be given as X

Matlab output
![A=[2 -1 10;-3 8 4]\\a=(A(1,1)*-A(1,2))+A(1,2)\\b=(A(2,1)*-A(1,2))+A(2,2)\\X=[A(1,1) a A(1,3); A(2,1) b A(2,3)]\\](https://tex.z-dn.net/?f=A%3D%5B2%20-1%2010%3B-3%208%204%5D%5C%5Ca%3D%28A%281%2C1%29%2A-A%281%2C2%29%29%2BA%281%2C2%29%5C%5Cb%3D%28A%282%2C1%29%2A-A%281%2C2%29%29%2BA%282%2C2%29%5C%5CX%3D%5BA%281%2C1%29%20a%20A%281%2C3%29%3B%20A%282%2C1%29%20b%20A%282%2C3%29%5D%5C%5C)
Generally the matrix that makes row 2 of matrix A equal to first row of A multiplied by the negative of the first element of row 2 plus the original row is
