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AVprozaik [17]
3 years ago
12

Hurry plz will give u brainliest

Mathematics
1 answer:
max2010maxim [7]3 years ago
7 0

Answer:

3

Step-by-step explanation:

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Given that the antiderivative of f of x equals 1 divided by the quantity x squared plus 1 is F(x) = tan-1(x) + C, evaluate the i
andreyandreev [35.5K]

Answer:

You know that if f(x) = 1/(x²+1) then F(x)=arctan(x).

What is arctan(x) function? It is inverse function of tan(x) in tge range (-π/2, π/2).

So if tan(x) = y then x = arctan(y)

therefore arctan(-1) = -π/4 because tan(-π/4)=-1 and arctan(1)=π/4 because tan(π/4) = 1.

In conclusion:

integral (dx/(x²+1)) from -1 to 1 =

= F(1) - F(-1) = arctan(1) - arctan(-1) =

=π/4-(-π/4)=π/4+π/4 = π/2.

answer B is correct

4 0
4 years ago
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Find the x-Intercept and the y-Intercept of the line below. Click on "None" if applicable.<br> None
PSYCHO15rus [73]

Answer: X-intercept is (2,0)

Y-intercept is (0,-2)

Step-by-step explanation:

3 0
3 years ago
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Is the height of a person and the person's age linear?Why or why not?
abruzzese [7]
Its not linear because growth rates vary with age, gender also plays a role in the change
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Please help me :(<br><br>I am in Great trouble:(​
Komok [63]

Answer: (I am not a maths moderator)

x=4

Step-by-step explanation:

Multiply the exponents

(2x-4)^12=(4^2)^6 (exponents multiply so)

(2x-4)^12=4^12

4^12 = 16777216

(2x-4)^12= 16777216

Take the 1/12 exponent for both sides

that will remove the ^12 exponent from the left side and will take the 12th root for the right.

2x-4=4

add 4 to both sides

2x=8

divide both sides by 2

x=4

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3 years ago
PLEASE HELP 30 POINTS.
Nookie1986 [14]

Answer:


Step-by-step explanation:

Note that the four input values, {3,4,6,11}, are all unique.  Each has exactly one y value associated with it.  This is an important criterion when we're deciding whether a relation is a function or not.

Suppose that we added one more input and its associated output:

{3,4,4,6,11}

If it happened that different values of y were associated with the two 4's, then we know immediatel that this relation is not a function.

5 0
4 years ago
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