Answer: 334
Step-by-step explanation:
6 consecutive numbers can be written as:
n, n+1, n+2, n + 3, n + 4, n + 5,
The addition of those 6 numbers is:
n + n+1 + n+2 + n + 3 + n + 4 + n + 5
6n + 1 + 2 + 3 + 4 + 5 = 6n + 15
Let's find the maximum n possible:
6n + 15 = 2020
6n = 2020 - 15 = 2005
n = 2005/6 = 334.16
The fact that n is a rational number means that 2020 is can not be constructed by adding six consecutive numbers, but we know that with n = 334 we can find a number that is smaller than 2020, and with n = 335 we can found a number bigger than 2020.
So with n = 334 we can find one smaller.
6*334 + 15 = 2019
and we can do this for all the values of n between 1 and 334, this means that we have 334 numbers less than 2020 that can be written as a sum of six consecutive positive numbers.
The lowest term would be 16.6
Step-by-step explanation:
x - 12 < 15
x < 15 + 12
x < 27
For x < 27 , i will add a number smaller than 27.
x = {26,25,24,23, etc}
Answer:
(-4, -7) (-3, 5) (1, 3) (9, 19)
Step-by-step explanation:
Plug in the values of x (the domain numbers) into the equation to solve for the range values (y)
For example, for the x value of -4
y= 2(-4)+1
y= -8+1
y= -7
Hey there!
For all this, we'll start with defining any variable as "a number", as we're using words.
a) Three less than the product of five and a number.
b) Two times the sum of x and y.
c) Three subtracted from the sum of a number and five.
Hopefully this helps!
