All of these points have the same y coordinate so this is a horizontal line which has a slope of 0.
Well what you want is y = mx + b
m = slope
b = intercept for y
with that just substitute in the slope and the intercept, but leave the x and y as it is. So later on you can put in a x coordinate and get the y coordinate through that, hope this helps!
Answer:
1/2
Step-by-step explanation:
It may be easier to start from
.. a(x +3)(x -1) = 0
.. a(x^2 +2x -3) = 0
The quadratic
.. ax^2 +bx +c = 0 will have solutions -3 and 1 for ...
.. a ≠ 0
.. b = 2a
.. c = -3a