Answer:
<u>II. Second table</u>
A B Total
C 0.25 0.75 1.00
D 0.35 0.65 1.00
Total 0.30 0.70 1.00
Explanation:
<h2>Tables</h2>
<u>I. First table </u>
A B Total
C 0.25 0.25 0.50
D 0.25 0.25 0.50
Total 0.50 0.25 1.00
<u>II. Second table</u>
A B Total
C 0.25 0.75 1.00
D 0.35 0.65 1.00
Total 0.30 0.70 1.00
<u>III. Third table</u>
<u></u>
A B Total
C 0.75 0.25 0.50
D 0.25 0.75 0.50
Total 0.50 0.50 1.00
<u>IV. Fourth table</u>
A B Total
C 0.65 0.35 1.00
D 0.35 0.65 1.00
Total 1.00 1.00 1.00
<h2>Solution</h2>
A <em>conditional relative frequency table</em> shows the relative frequencies determined upon a row or column.
There are two types of relative conditional frequency table: 1) row conditional relative frequency, and 2) column conditional relative frequency.
When you divide the joint frequency by the marginal frequency of the column total you have the row conditional frequency table. When you dividethe joint frequency by the row total you have the colum conditional frequency table.
In a row conditional relative frequency each total of the right hand column equals 1. This is the case of the second table.
In a column conditional relative frequency each total of the bottom row equals 1. This is not happening with any of the shown tables.
Hence, only the second table could be a conditional relative frequency table.
<h3>You are correct. Nice work.</h3>
You should find that each side is 5 units long, so you have a rhombus. Also, each angle is 90 degrees so you have a rectangle. Combine the properties of a rhombus and a rectangle and you get a square as the best description.
There are 4 possibilities for cone or cup to hold your ice cream. There are 3 different sizes to choose from. There are 20 flavors of ace-cream, and then 15 choices of topping. Assuming you must choose 1 flavor of ice cream and 1 topping as the question implies, there are then 4*3*20*15 = 3600 different combinations to choose from. Answer is D: 3600
Note: The missing diagram is attached below for a reference.
Answer:
Step-by-step explanation:
Given:
- ∠T and ∠V are right angles.
-
║ 
To Prove:
- Δ
≅ Δ
As
∠ 
≅ ∠ 
≅ 
(Given)
Side 
≅
║ 
and is a transverse
So,
∠ 
≅ ∠ 
![\left[alternate\:\:interior\:\:angles\right]](https://tex.z-dn.net/?f=%5Cleft%5Balternate%5C%3A%5C%3Ainterior%5C%3A%5C%3Aangles%5Cright%5D)
Thus,
- Δ ≅ Δ
Keywords: proof, paragraph, logic, reason
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case.
