Pls help i just begin lazzy
2 answers:
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Answer:
Step-by-step explanation:
a) the sample point of the random experiment is 36
b) (1,1) (1,2) (1,3) (1,4) (1,5) (1,6)
(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)
(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)
(4,1) (4,2) (4,3) (4,4) (4,5) (4,6)
(5,1) (5,2) (5,3) (5,4) (5,5) (5,6)
(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)
Only (1,1) will sum to give 2.
(1,2) and (2,1) will sum up to give 3.
(1,3), (2,2) (3,1) will sum up to give 4.
(1,4) (2,3) (3,2) (4,1) will sum up to give 5.
(1,5) (2,4) (3,3) (4,2) (5,1) will sum up to give 6
(1,6) (2,5) (3,4) (4,3) (5,2) (6,1) will sum up to give 7
(2,6) (3,5) (4,4) (5,3) (6,2) will sum up to give 8
(3,6) (4,5) (5,4) (6,3) will sum up to give 9
(4,6) (5,5) (6,4) will sum up to give 10
(5,6) (6,5) will sum up to give 11
(6,6) 1ill sum up to give 12.
c) probability of obtaining a value of 5 = (number of possible times 5 will occur)/ (total outcome) =
d) probability of obtaining a value of 8 or greater =
e) yes, since the total number is 11 and probability of obtaining odd number is and probability of obtaining even number is
.
P(odd)P(even)
f) emprical method was used