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Alla [95]
3 years ago
10

Select the correct answer.

Mathematics
1 answer:
dolphi86 [110]3 years ago
6 0

Answer:

your answer gonna be the letter D 20

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The total monthly profit for a firm is P(x)=6400x−18x^2− (1/3)x^3−40000 dollars, where x is the number of units sold. A maximum
wlad13 [49]

Answer:

Maximum profits are earned when x = 64 that is when 64 units are sold.

Maximum Profit = P(64) = 2,08,490.666667$

Step-by-step explanation:

We are given the following information:P(x) = 6400x - 18x^2 - \frac{x^3}{3} - 40000, where P(x) is the profit function.

We will use double derivative test to find maximum profit.

Differentiating P(x) with respect to x and equating to zero, we get,

\displaystyle\frac{d(P(x))}{dx} = 6400 - 36x - x^2

Equating it to zero we get,

x^2 + 36x - 6400 = 0

We use the quadratic formula to find the values of x:

x = \displaystyle\frac{-b \pm \sqrt{b^2 - 4ac} }{2a}, where a, b and c are coefficients of x^2, x^1 , x^0 respectively.

Putting these value we get x = -100, 64

Now, again differentiating

\displaystyle\frac{d^2(P(x))}{dx^2} = -36 - 2x

At x = 64,  \displaystyle\frac{d^2(P(x))}{dx^2} < 0

Hence, maxima occurs at x = 64.

Therefore, maximum profits are earned when x = 64 that is when 64 units are sold.

Maximum Profit = P(64) = 2,08,490.666667$

6 0
3 years ago
Given that KD is congruent to AT prove that angle K is congruent to angle T
Mademuasel [1]

KD is congruent to AT as:

<h3>angles are of equal measure</h3><h3>sides KD and TA are equal</h3><h3>sides DT and KA are equal</h3>

The figure is kite as has two pairs of same sides.

<h3>They are constructed in a way of having same angle.</h3>
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2 years ago
Lawrence bought 2/3 pound of roast beef. He used 3/4 of it to make a sandwich. How much roast beef did Lawrence use for his sand
laila [671]
You multiply 3/4 by 2/3 it equals 2/4 which equals 1/2. The answer is 1/2.
3 0
3 years ago
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WILL GIVE BRAINLIESTT!!
djyliett [7]

Answer:

y =   {e}^{3}

Step-by-step explanation:

f(x) =  {e}^{3x}  \\  \\ plug \: x = 1 \\  \\ f(1) =  {e}^{3 \times 1}  \\  \\ f(1) =  {e}^{3}   \\  \\ plug \: f(1) = y \\  \\ y =   {e}^{3}

8 0
3 years ago
Examine the following diagram:
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Answer:

b

Step-by-step explanation:

i just took it on edge

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