All categories

3 years ago

Need help with this question

Mathematics

1 answer:

goldfiish [28.3K]3 years ago

4 0

Answer:

x = 12

Step-by-step explanation:

Complementary angles add up to have a sum of 90 degrees. We can create an equation and solve for x.

3x + 6x - 18 = 90

~Simplify

9x - 18 = 90

~Add 18 to both sides

9x = 108

~Divide 9 to both sides

x = 12

Best of Luck!

You might be interested in

What does -6(-7 - 3k)

Zina [86]

Here, Just apply Distributive property which tells, a(b + c) = ab + bc
So, -6(-7 - 3k) = 42 + 18k

In short, Your Answer would be 42 +18k

Hope this helps!

4 0

2 years ago

Given two angles that measure 50 degrees and 90 degrees and a side that measures 4 feet

kupik [55]

What is the question? Please specific!

7 0

3 years ago

Read 2 more answers

Lines DE and AB intersect at point C.

alexandr402 [8]

Answer:

Step-by-step explanation:

2x+2+5x+3=180 (angles on a straight line)

7x+5=180

7x=180-5

7x=175

x=25 (dividing both sides by 7)

3 0

3 years ago

Solve the given initial-value problem. the de is of the form dy dx = f(ax + by + c), which is given in (5) of section 2.5. dy dx

shutvik [7]

$\dfrac{\mathrm dy}{\mathrm dx}=\cos(x+y)$

Let $v=x+y$ , so that $\dfrac{\mathrm dv}{\mathrm dx}-1=\dfrac{\mathrm dy}{\mathrm dx}$ :

$\dfrac{\mathrm dv}{\mathrm dx}=\cos v+1$

Now the ODE is separable, and we have

$\dfrac{\mathrm dv}{1+\cos v}=\mathrm dx$

Integrating both sides gives

$\displaystyle\int\frac{\mathrm dv}{1+\cos v}=\int\mathrm dx$

For the integral on the left, rewrite the integrand as

$\dfrac1{1+\cos v}\cdot\dfrac{1-\cos v}{1-\cos v}=\dfrac{1-\cos v}{1-\cos^2v}=\csc^2v-\csc v\cot v$

Then

$\displaystyle\int\frac{\mathrm dv}{1+\cos v}=-\cot v+\csc v+C$

and so

$\csc v-\cot v=x+C$

$\csc(x+y)-\cot(x+y)=x+C$

Given that $y(0)=\dfrac\pi2$ , we find

$\csc\left(0+\dfrac\pi2\right)-\cot\left(0+\dfrac\pi2\right)=0+C\implies C=1$

so that the particular solution to this IVP is

$\csc(x+y)-\cot(x+y)=x+1$

5 0

2 years ago

A rectangular deck has an area of 320ft^2. the length of the deck is 4 feet longer than the width. find the dimensions of the de

Digiron [165]

A = L * W
A = 320
L = W + 4

320 = W(W + 4)
320 = W^2 + 4W
W^2 + 4W = 320
W^2 + 4W + 4 = 320 + 4
(W + 2)^2 = 324
W + 2 = (+-) sqrt 324
W = -2 (+-) 18

W = -2 + 18 = 16 ft <== this is the width
W = -2 - 18 = -20....not this one because it is negative

L = W + 4
L = 16 + 4
L = 20 ft <=== this is the length

in summary...the width is 16 ft and the length is 20 ft

7 0

3 years ago