Combinations of 7 taken 4 at a time.
C (7,4) = 7! /[ 4!(3!)]
7 x 6 x 5 = 210
210 divided by 3 = 70
70 divided by 2 = 35
A. Whole number- a number that is whole, with no decimals or extra signs or variables next to or part of it.
b. Digit- a number from 0-9 is a digit.
c. The position a number has in a larger number. ex. Hundreds, Tens, and One's place
d. A number rounded to a whole number. Either to a smaller or larger to make it whole and easier to understand.
e. Equals: Numbers that equal each other.
I hope this helps you.
Brainliest answer would be appreciated!
The value of x is 2yw + y - 1 for the given equation 2x + 2/y = 4w + 2.
According to the given question.
We have an equation
2x + 2/y = 4w + 2
Since, we have to find the value of x for the given equation
2x + 2/y = 4w + 2
Thereofore,
2x + 2/y = 4w + 2
⇒ 2(x + 1)/y = 2(2w + 1) (taking 2 common from both the sides)
⇒ (x + 1)/y = 2w + 1
⇒ (x + 1) = y(2w + 1) (multiplying both the sides by y)
⇒ x + 1 = 2yw + y
⇒ x = 2yw + y - 1 ( subtracting 1 both the sides)
Hence, the value of x is 2yw + y - 1 for the given equation 2x + 2/y = 4w + 2.
Find out more information about equation here:
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Answer:
Therefore, the probability that at least half of them need to wait more than 10 minutes is <em>0.0031</em>.
Step-by-step explanation:
The formula for the probability of an exponential distribution is:
P(x < b) = 1 - e^(b/3)
Using the complement rule, we can determine the probability of a customer having to wait more than 10 minutes, by:
p = P(x > 10)
= 1 - P(x < 10)
= 1 - (1 - e^(-10/10) )
= e⁻¹
= 0.3679
The z-score is the difference in sample size and the population mean, divided by the standard deviation:
z = (p' - p) / √[p(1 - p) / n]
= (0.5 - 0.3679) / √[0.3679(1 - 0.3679) / 100)]
= 2.7393
Therefore, using the probability table, you find that the corresponding probability is:
P(p' ≥ 0.5) = P(z > 2.7393)
<em>P(p' ≥ 0.5) = 0.0031</em>
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Therefore, the probability that at least half of them need to wait more than 10 minutes is <em>0.0031</em>.
The answer would be 1/4 or
i hope this answer helps!
