We have the following function that is a
quadratic function:
So the graph of this function is shown in the figure below. This is a <em>parabola</em> as you can see. The roots of this functions, that is, the x-intercepts are:
As you can see in the figure. This function decreases from
and increases from
Finally, another thing we can see from the graph is that the vertex is the point:
Answer:
330
Step-by-step explanation:
1
112
+218
____
330
Let's define variables:
s = original speed
s + 12 = faster speed
The time for the half of the route is:
60 / s
The time for the second half of the route is:
60 / (s + 12)
The equation for the time of the trip is:
60 / s + 60 / (s + 12) + 1/6 = 120 / s
Where,
1/6: held up for 10 minutes (in hours).
Rewriting the equation we have:
6s (60) + s (s + 12) = 60 * 6 (s + 12)
360s + s ^ 2 + 12s = 360s + 4320
s ^ 2 + 12s = 4320
s ^ 2 + 12s - 4320 = 0
We factor the equation:
(s + 72) (s-60) = 0
We take the positive root so that the problem makes physical sense.
s = 60 Km / h
Answer:
The original speed of the train before it was held up is:
s = 60 Km / h
9514 1404 393
Answer:
{2.96, 12.66}
Step-by-step explanation:
A graph shows the rocket will be 600 feet up after 2.96 seconds, and again at 12.66 seconds.
__
You can solve the equation h = 600 to find the times.
-16t^2 +250t = 600
-16(t^2 -15.625t) = 600
-16(t^2 -15.625t +7.8125²) = 600 -16(7.8125²)
-16(t -7.8125)² = -376.5625
t -7.8125 = √(376.5625/16) ≈ ±4.8513
t = 7.8125 ± 4.8513 ≈ {2.9612, 12.6638}
The rocket will be 600 ft above the ground 2.96 and 12.66 seconds after launch.
No, 2 of the 5x7 would actually take up. 10x14
