Answer:
C. x > 5 or x < - 3
Step-by-step explanation:
Step 1:
x - 1 > 4
x > 4 + 1
x > 5
Step 2:
x - 1 < -4
x < -4 + 1
x < -3
HP: {x > 5 or x < -3} (c)
Answer:
The IQR is given by:

If we want to find any possible outliers we can use the following formulas for the limits:


And if we find the lower limt we got:


So then the left boundary for this case would be 3 days
Step-by-step explanation:
For this case we have the following 5 number summary from the data of 144 values:
Minimum: 9 days
Q1: 18 days
Median: 21 days
Q3: 28 days
Maximum: 56 days
The IQR is given by:

If we want to find any possible outliers we can use the following formulas for the limits:


And if we find the lower limt we got:


So then the left boundary for this case would be 3 days
Answer:
The amount in the account after six years is $2,288.98
Step-by-step explanation:
In this question, we are asked to calculate the amount that will be in an account that has a principal that is compounded quarterly.
To calculate this amount, we use the formula below
A = P(1+r/n)^nt
Where P is the amount deposited which is $1,750
r is the rate which is 4.5% = 4.5/100 = 0.045
t is the number of years which is 6 years
n is the number of times per year, the interest is compounded which is 4(quarterly means every 3 months)
we plug these values into the equation
A = 1750( 1 + 0.045/4)^(4 * 6)
A = 1750( 1 + 0.01125)^24
A = 1750( 1.01125)^24
A = 2,288.98
The amount in the account after 6 years is $2,288.98
Answer:
-6i
Step-by-step explanation:
Complex roots always come in pairs, and those pairs are made up of a positive and a negative version. If 6i is a root, then its negative value, -6i, is also a root.
If you want to know the reasoning, it's along these lines: to even get a complex/imaginary root, we take the square root of a negative value. When you take the square root of any value, your answer is always "plus or minus" whatever the value is. The same thing holds for complex roots. In this case, the polynomial function likely factored to f(x) = (x+8)(x-1)(x^2+36). To solve that equation, you set every factor equal to zero and solve for the x's.
x + 8 = 0
x = -8
x - 1 = 0
x = 1
x^2 + 36 = 0
x^2 = -36 ... take the square root of both sides to get x alone
x = √-36 ... square root of an imaginary number produces the usual square root and an "i"
x = ±6i
Answer:
This is the answer
Step-by-step explanation: